Re: [EBOB-DISCUSS] what if a constructor argument declares a thrown exception?

[Liam M. <lm...@wp...>]

Meant to send this to the list, sorry.

-------- Original Message --------
I'm confused, this works just fine (attached). My test case looks like this:

    public void testFooBah()
    {
        Foo foo2 = new Foo();
        Bah bah2 = new Bah(foo2.getIntValue());
    }

and that fails to compile due to the uncaught exception, but everything 
else is fine.

Liam


Gary Pollice wrote:

>What do you mean "everything succeeded?" This should not result in the
>creation of a new Bah because you don't have a valid argument.
>
>	--Gary 
>
>-----Original Message-----
>From: ebo...@li...
>[mailto:ebo...@li...] On Behalf Of Liam
>Morley
>Sent: Monday, December 13, 2004 3:34 PM
>To: ebo...@li...
>Subject: [EBOB-DISCUSS] what if a constructor argument declares a thrown
>exception?
>
>Let's say we have a class Foo:
>
>Class Foo {
>    int getIntValue() throws Exception {
>       return 4;
>    }
>}
>
>and a class Bah:
>
>Class Bah {
>    Bah (int i) {}
>}
>
>What if we add a Foo object to the bench "foo1", and then try to add a Bah
>object to the bench using "foo1.getIntValue()" as a parameter in the
>constructor? Java would say we need to catch that exception somewhere, but
>where?
>
>I tried this in BlueJ... Everything succeeded, and I wasn't alerted to the
>uncaught Exception. I recorded a Unit test, which succeeded; however, when I
>opened the unit test and tried to compile it, it failed.
>
>Liam
>
>
>
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