Re: [Dev-C++] Question about increment..

[Mani <man...@gm...>]

Thanks for all the comments.. I had posted to mingw-users mailing list
as well, I had lots of good responses there (I had posted here w/o
looking at those responses..)

for those interested, you can see these at:
http://sourceforge.net/mailarchive/forum.php?thread_name=5058E683.1010205%40users.sourceforge.net&forum_name=mingw-users

thanks once again for your time.

best, murali.

On Thu, Sep 20, 2012 at 2:15 PM, Brothers, Robert
<rob...@tq...> wrote:
> Murali,
>
> I'm not a C++ programmer (use C# mostly), but I put your original code
> into Visual Studio C++.net and it gave the c = 6 result as well.
>
> The code Mani offered ( ++a + ++b + a + b) gave the value of 10 (which I
> tend to feel is understandable since the value of a and b are
> incremented first then 2 + 3 + 2 + 3 = 10).
>
> If I write the code as:
>
> int a = 1, b = 2;
> int c = a++ + b++;
> c += a + b;
>
> I DO get 8 as the result.
>
> Also, in C#, your original code give 8 as you found in Java.
>
> As I said, I'm not a C++ programmer (I'm a EE not a programmer;^)
>
> Regards
> Bob
>
>
>
> -----Original Message-----
> From: Mani [mailto:man...@gm...]
> Sent: Thursday, September 20, 2012 1:09 PM
> To: a.geo
> Cc: dev...@li...
> Subject: Re: [Dev-C++] Question about increment..
>
> Hi,
>
> But this is not right, if I understand precedence rules correctly..
> ++ has higher precedence than addition.. your explanation seems to say
> that ++ is done after addition..
>
> In Java, the same expression gives 8.., and  I believe other C++
> compilers also gave 8 (I heard from others; I have not tested this
> myself -- I did test what happens in Java myself).
>
> I am inclined to think this looks like a bug..??
>
> thanks, murali.
>
> On Thu, Sep 20, 2012 at 1:04 PM, a.geo <aqu...@gm...> wrote:
>> Well, you really are doing the next
>>
>> int a = 1, b = 2;
>> int c = a + b + a + b;
>> a++;
>> b++;
>> This is why you get 6, remember the ++ is a prefix in this case, then,
> is
>> executed NEXT to the expression.
>>
>>
>> int c = ++a + ++b + a + b;
>> Well, if this compile correctly, give you the 8 value, because
>>
>> int a = 1, b = 2;
>> ++a;
>> ++b;
>> int c = a + b + a + b;
>>
>> 2012/9/20 Mani <man...@gm...>
>>>
>>> Hi,
>>>
>>> I recently to try some toy things in DevC++ (version I am using is
>>> 4.9.9.2)
>>>
>>> The code I had was this:
>>>
>>>     int a = 1, b = 2;
>>>     int c = a++ + b++ + a + b;
>>>
>>>     cout << "a = " << a << endl;
>>>     cout << "b = " << b << endl;
>>>     cout << "c = " << c << endl;
>>>
>>> I expected the c value to be 8 (by operator precedence, ++ has higher
>>> precedence than +, so do in order:
>>> a++, then b++
>>> then do (a++ + b++)
>>> then add the previous result and a
>>> then add the previous result and b
>>>
>>> but the answer I got was 6..
>>>
>>> what might be the reason for this..??
>>>
>>> thanks, murali
>>>
>
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