Re: [Dev-C++] Question about increment..

[Mani <man...@gm...>]

Hi,

But this is not right, if I understand precedence rules correctly..
++ has higher precedence than addition.. your explanation seems to say
that ++ is done after addition..

In Java, the same expression gives 8.., and  I believe other C++
compilers also gave 8 (I heard from others; I have not tested this
myself -- I did test what happens in Java myself).

I am inclined to think this looks like a bug..??

thanks, murali.

On Thu, Sep 20, 2012 at 1:04 PM, a.geo <aqu...@gm...> wrote:
> Well, you really are doing the next
>
> int a = 1, b = 2;
> int c = a + b + a + b;
> a++;
> b++;
> This is why you get 6, remember the ++ is a prefix in this case, then, is
> executed NEXT to the expression.
>
>
> int c = ++a + ++b + a + b;
> Well, if this compile correctly, give you the 8 value, because
>
> int a = 1, b = 2;
> ++a;
> ++b;
> int c = a + b + a + b;
>
> 2012/9/20 Mani <man...@gm...>
>>
>> Hi,
>>
>> I recently to try some toy things in DevC++ (version I am using is
>> 4.9.9.2)
>>
>> The code I had was this:
>>
>>     int a = 1, b = 2;
>>     int c = a++ + b++ + a + b;
>>
>>     cout << "a = " << a << endl;
>>     cout << "b = " << b << endl;
>>     cout << "c = " << c << endl;
>>
>> I expected the c value to be 8 (by operator precedence, ++ has higher
>> precedence than +, so do in order:
>> a++, then b++
>> then do (a++ + b++)
>> then add the previous result and a
>> then add the previous result and b
>>
>> but the answer I got was 6..
>>
>> what might be the reason for this..??
>>
>> thanks, murali
>>