ok ... hint #2
you need /, %, pow, 2 for loops, and a if
however my answer gives you one extra number, but I guess I could put it in a vector and pop the top.
if you want the code to look at ... e-mail me or the list
and put more of these kind of questions up, I love them.
-----Original Message-----
From: "Dario Peralta"<do...@ho...>
To: dev...@li...
Date: Thu Nov 15 04:10:37 PST 2001
Subject: [Dev-C++] Print numbers up to n digits wide of number system base m.
>
>/*
>Let m be an integer, greater than zero but less than eleven. Numerical
>strings, in which each digit is greater or equal to 0 but less than m, are
>numbers of the number system in the base m. The numbers 10110 and 1981, for
>example, are numbers of the number system in the base the 10, but only the
>first one is a number of the number system in the base 2. The zeros at the
>beginning of the number are leading zeros, unless the number is 0.
>
>Write a program that reads the integers m and n, and outputs all numbers of
>the number system in the base m containing n digits at the most, and without
>leading zeros. Each number may be output only once.
>
>You may assume that m is greater than 0, but less than 11, and that n is
>greater than 0 but less than 81.
>
>The numbers should be output on consecutive lines, one number per line
>*/
>
>I've been banging my head over this problem since last week, and i'm no
>closer to an answer than i was when i started.
>
>I find myself always coming back to the idea of implementing a bidimensional
>array as such: nsys[n][m]
>
>But i can't figure out the system of loops and conditions that would
>correctly solve this problem.
>
>I'm hopelessly stuck. I'll keep banging my head, but i doubt i'll answer
>this.
>
>I thought i'd ask for some help. Some clever hints would be better than the
>straight answer, as i would like to figure out as much of it by myself as i
>can. But i really need help.
>
>Thanks...
>
>adios,
>biterman.
>
><<That government is best which governs the least... that government is best
>which governs not at all.>>
>
>
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