dev-cpp-users

[Dev-C++] Casting Problem

[Tim S. <ti...@we...>]

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Hi List!

I have a problem with getting the floatpart from a float. My code to
do this
looks so atm:

double number;
number = number - (int)number;

but with this usage I always get 0 for number.  Does someone
know how to
get the floatpart and can tell me?

so long

Tim

- --
WE ARE TEH BORG!
     RESSISTANCE IS FUTILE!
   http://we-are-teh-b.org/~tim/borg.key
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Re: [Dev-C++] Casting Problem

[Michael D. S. <for...@hi...>]

I know one thing, It can be done.

I did it, late last night as an error. It was driving me nuts until I found 
it. Unfortunately, it was late, and I cannot duplicate the results now. I 
think it had something to do with some parentheses being -- not quite right 
:) But I'm not sure.

It's just the one liner that's a trick. Certainly a little longer version 
will work easily.

int wholenumber;
double number;
double decimal;

wholenumber = int number;
decimal = number - wholenumber;

That's untested, and I'm still occasionally mixing in some PERL, so... 
caveat emptor.

ms

At 08:55 AM 9/28/03, you wrote:
>-----BEGIN PGP SIGNED MESSAGE-----
>Hash: SHA1
>
>Hi List!
>
>I have a problem with getting the floatpart from a float. My code to
>do this
>looks so atm:
>
>double number;
>number = number - (int)number;
>
>but with this usage I always get 0 for number.  Does someone
>know how to
>get the floatpart and can tell me?
>
>so long
>
>Tim
>
>- --
>WE ARE TEH BORG!
>     RESSISTANCE IS FUTILE!
>   http://we-are-teh-b.org/~tim/borg.key
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>iD8DBQE/dugtsMXChvH2qP0RArldAKCyN/oDTMOkppsAneVfnc2laQaRSACgmfHN
>yEoHOoLKPP+n/OzQ6Dsy05A=
>=aDJe
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>
>
>
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Re: [Dev-C++] Casting Problem

[Per W. <pw...@ia...>]

#include <iostream>
#include <cmath>

int main() {
    double n1 = 1.75;
    double n2 = -1.75;
    std::cout << "Fract n1 = " << (n1 - (int)n1)
	<< ", n1 = " << (n2 - (int)n2) << std::endl;
    std::cout << "Fract n1 = " << (n1 - floor(n1))
	<< ", n2 = " << (n2 - floor(n2))<< std::endl;
    std::cout << "Fract n1 = " << fmod(n1,1.0)
	<< ", n2 = " << Bfmod(n2,1.0) << std::endl;
    return 0;
}

will output:
Fract n1 = 0.75, n1 = -0.75
Fract n1 = 0.75, n2 = 0.25
Fract n1 = 0.75, n2 = -0.75

Note that the (n - (int)n) alternative is only valid within the numeric
range of an int...

/Per W

On Sun, 28 Sep 2003, Tim Schumacher wrote:

> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> Hi List!
>
> I have a problem with getting the floatpart from a float. My code to
> do this
> looks so atm:
>
> double number;
> number = number - (int)number;
>
> but with this usage I always get 0 for number.  Does someone
> know how to
> get the floatpart and can tell me?
>
> so long
>
> Tim
>
> - --
> WE ARE TEH BORG!
>      RESSISTANCE IS FUTILE!
>    http://we-are-teh-b.org/~tim/borg.key
> -----BEGIN PGP SIGNATURE-----
> Version: GnuPG v1.0.6 (MingW32) - WinPT 0.5.6
>
> iD8DBQE/dugtsMXChvH2qP0RArldAKCyN/oDTMOkppsAneVfnc2laQaRSACgmfHN
> yEoHOoLKPP+n/OzQ6Dsy05A=
> =aDJe
> -----END PGP SIGNATURE-----
>
>
>
> -------------------------------------------------------
> This sf.net email is sponsored by:ThinkGeek
> Welcome to geek heaven.
> http://thinkgeek.com/sf
> _______________________________________________
> Dev-cpp-users mailing list
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Re: [Dev-C++] Casting Problem

[Tim S. <ti...@we...>]

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Hi People,

thanks for your answers. The fault was my own stupidy, since the
input variable was int and so it could not get the float part
because it didn't had one :)

so long

Tim


- --
WE ARE TEH BORG!
~    RESSISTANCE IS FUTILE!
~  http://we-are-teh-b.org/~tim/borg.key
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