dev-cpp-users

[Dev-C++] Long double printf

[James M. <mad...@ya...>]

Can someone tell me how to use printf to display a long double type 
variable. I've tried code along the lines of:

long double ld=1.0L;
printf("%Lg", ld);

but that displays "0" rather than "1". I've tried similar with all other 
combinations of modifier/type that
I can think of.



		
___________________________________________________________ 
How much free photo storage do you get? Store your holiday 
snaps for FREE with Yahoo! Photos http://uk.photos.yahoo.com

Re: [Dev-C++] Long double printf

[Per W. <pw...@ia...>]

I don't think that you can.

When using Dev-C++, your program will be linked against the M$ C run-time
libraries, and to my knowledge they don't support the long double type.

You have to typecast your variable to double before printing it - giving
up the extra range and precision.

When printing 64-bit integers, you have a similar problem.

Using gcc on a unix machine you can write:
printf("Number = %Lu\n",n);

Using gcc on Windows, you have to emit a 64-bit integer using:
printf("Number = %I64u\n",n);

/Per W

On Sat, 12 Nov 2005, James Maddison wrote:

> Can someone tell me how to use printf to display a long double type
> variable. I've tried code along the lines of:
>
> long double ld=1.0L;
> printf("%Lg", ld);
>
> but that displays "0" rather than "1". I've tried similar with all other
> combinations of modifier/type that
> I can think of.

Re: [Dev-C++] Long double printf

[Per W. <pw...@ia...>]

Forgot to write the:
printf("Number = %llu\n",n);
integer alternative when building on a unix box.

/Per W

On Sat, 12 Nov 2005, Per Westermark wrote:

> I don't think that you can.
>
> When using Dev-C++, your program will be linked against the M$ C run-time
> libraries, and to my knowledge they don't support the long double type.
>
> You have to typecast your variable to double before printing it - giving
> up the extra range and precision.
>
> When printing 64-bit integers, you have a similar problem.
>
> Using gcc on a unix machine you can write:
> printf("Number = %Lu\n",n);
>
> Using gcc on Windows, you have to emit a 64-bit integer using:
> printf("Number = %I64u\n",n);
>
> /Per W
>
> On Sat, 12 Nov 2005, James Maddison wrote:
>
> > Can someone tell me how to use printf to display a long double type
> > variable. I've tried code along the lines of:
> >
> > long double ld=1.0L;
> > printf("%Lg", ld);
> >
> > but that displays "0" rather than "1". I've tried similar with all other
> > combinations of modifier/type that
> > I can think of.
>
>