Thread: Re: [Dev-C++] Pointer to function

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Hello All,
// ------------------------main.h----------------
#include <iostream>
#include <stdlib.h>

class A
{
   public:
       int f ();
};

int A::f(void)
{
   return 5;
};
//----------------------------main.cpp--------------------------------------------- 

#include "main.h"

using namespace std;

int main(int argc, char *argv[])
{
       A cA;

       int *pFunc;
       *pFunc = cA.f();
              //        cout << ??? How I can call cA.f() using the 
pointer pFunc?
       /* Direct Acces to the Function */
       printf("printf -    f() : %d \t |\t",cA.f());
       cout << "COUT -    f() : " << cA.f() << endl;
             /* Acces with the pointeur *pFunc */
       printf("printf - *pFunc : %x\ \t | \t",*pFunc);
       cout << "COUT - *pFunc : " << *pFunc << endl;
             /* Address of the pointeur *pFunc */
       printf("printf - &pFunc : %x\ | \t",&pFunc);
       cout << "COUT - &pFunc : " << &pFunc << endl;
       system("PAUSE");              return 0;
}

Is that Right?

but how to acces to the Direct Adress of the function f()?

Thread: Re: [Dev-C++] Pointer to function

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