dev-cpp-users

[Dev-C++] Can I handle 64 bits with unsigned long long int ?

[Roberto R. <rob...@ar...>]

Hi all,

Can I handle 64 bits numbers with unsigned long long ?

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>

unsigned long long int D0,D1 ;
        
int main(int argc, char *argv[])
{
  D0 = 0;
  D1 = 0xffffffffffff; /*  I put first unsigned long int, compiler 
alerts about truncated number...) */
  gotoxy(1,9);printf ("Num hexa : ");
  scanf ("%x",&D0); /*can handle whatever up to 32 bits*/
  gotoxy(1,11);printf ("Dec0: %lu\nDec1: %lu\n\n", D0, D1);
 
  getchar();  getchar();
  return 0;
}
/*
Results:

Dec0 : 4294967295 mean ok if I put just up to 0xffffffff  32bits
Dec1 : 0  ??
*/

Why is ever truncated in 32 bits, how can handle long long to get up to 
64 bits numbers ?

Thanks in advance

Roberto

RE: [Dev-C++] Can I handle 64 bits with unsigned long long int ?

[Ioannis V. <iv...@em...>]

Question about C99. That is a first! See below:



> -----Original Message-----
> From: dev...@li...=20
> [mailto:dev...@li...] On Behalf=20
> Of Roberto Ricardi
> Sent: Sunday, April 06, 2003 2:11 AM
> To: 'Dev-C++ -Users-List'
> Subject: [Dev-C++] Can I handle 64 bits with unsigned long long int ?
>=20
>=20
> Hi all,
>=20
> Can I handle 64 bits numbers with unsigned long long ?
>=20
> #include <stdio.h>
> #include <stdlib.h>
> #include <conio.h>
>=20
> unsigned long long int D0,D1 ;
>        =20
> int main(int argc, char *argv[])
> {
>   D0 =3D 0;
>   D1 =3D 0xffffffffffff; /*  I put first unsigned long int, compiler=20
> alerts about truncated number...) */
>   gotoxy(1,9);printf ("Num hexa : ");
>   scanf ("%x",&D0); /*can handle whatever up to 32 bits*/
>   gotoxy(1,11);printf ("Dec0: %lu\nDec1: %lu\n\n", D0, D1);
> =20
>   getchar();  getchar();
>   return 0;
> }
> /*
> Results:
>=20
> Dec0 : 4294967295 mean ok if I put just up to 0xffffffff  32bits
> Dec1 : 0  ??
> */
>=20
> Why is ever truncated in 32 bits, how can handle long long to=20
> get up to=20
> 64 bits numbers ?


unsigned long long is not guaranteed to be 64-bit. If you want an =
unsigned
integral type to be at least 64-bit, you have to do:


#include <stdint.h>

// ...

uint_least64_t D0, D1;

 // ...



which is a typedef of the closest to 64-bit type provided by platform
(closest from above, that is if unsigned long is 32 bit and unsigned =
long
long is 128 bit for example, the typedef will be of unsigned long long).


I read it straight from the standard. I do not know whether MINGW has
implemented it (and as far as I know these facilities are "optional", if =
the
platform doesn't support >=3D64 bit, will not have the above type =
naturally).


By the way, have you got any book regarding C99? If yes, can you please =
tell
me which?




Ioannis Vranos
=20
* Programming pages: http://www.noicys.freeurl.com
* Alternative URL: http://run.to/noicys


Anti-racism movement: http://www.positive-youthfoundation.org
Iraq Peace Pledge: http://www.peacepledge.org

Re: [Dev-C++] Can I handle 64 bits with unsigned long long int ?

[Roberto R. <rob...@ar...>]

Hi all,

Sorry was not here by the while. IM learn about C & C++ standares just 
here, at dev-cpp list. Im not a expert programmer, using I64 I can 
handle 64 bits hexa friendly. I use it to work with comunications 
protocols, industrial controls, etc.

....
scanf ("%I64x",&Dato);
gotoxy(1,11);printf ("Dec0: %I64u\nDec1: %I64u\n\n", Dato, Dato1);
....

Will try to ask some friends about  C99 books :)

Thanks Ioannis

Roberto


Ioannis Vranos wrote:

>Question about C99. That is a first! See below:
>
>
>
>  
>
>>-----Original Message-----
>>From: dev...@li... 
>>[mailto:dev...@li...] On Behalf 
>>Of Roberto Ricardi
>>Sent: Sunday, April 06, 2003 2:11 AM
>>To: 'Dev-C++ -Users-List'
>>Subject: [Dev-C++] Can I handle 64 bits with unsigned long long int ?
>>
>>
>>Hi all,
>>
>>Can I handle 64 bits numbers with unsigned long long ?
>>
>>#include <stdio.h>
>>#include <stdlib.h>
>>#include <conio.h>
>>
>>unsigned long long int D0,D1 ;
>>        
>>int main(int argc, char *argv[])
>>{
>>  D0 = 0;
>>  D1 = 0xffffffffffff; /*  I put first unsigned long int, compiler 
>>alerts about truncated number...) */
>>  gotoxy(1,9);printf ("Num hexa : ");
>>  scanf ("%x",&D0); /*can handle whatever up to 32 bits*/
>>  gotoxy(1,11);printf ("Dec0: %lu\nDec1: %lu\n\n", D0, D1);
>> 
>>  getchar();  getchar();
>>  return 0;
>>}
>>/*
>>Results:
>>
>>Dec0 : 4294967295 mean ok if I put just up to 0xffffffff  32bits
>>Dec1 : 0  ??
>>*/
>>
>>Why is ever truncated in 32 bits, how can handle long long to 
>>get up to 
>>64 bits numbers ?
>>    
>>
>
>
>unsigned long long is not guaranteed to be 64-bit. If you want an unsigned
>integral type to be at least 64-bit, you have to do:
>
>
>#include <stdint.h>
>
>// ...
>
>uint_least64_t D0, D1;
>
> // ...
>
>
>
>which is a typedef of the closest to 64-bit type provided by platform
>(closest from above, that is if unsigned long is 32 bit and unsigned long
>long is 128 bit for example, the typedef will be of unsigned long long).
>
>
>I read it straight from the standard. I do not know whether MINGW has
>implemented it (and as far as I know these facilities are "optional", if the
>platform doesn't support >=64 bit, will not have the above type naturally).
>
>
>By the way, have you got any book regarding C99? If yes, can you please tell
>me which?
>
>
>
>
>Ioannis Vranos
> 
>* Programming pages: http://www.noicys.freeurl.com
>* Alternative URL: http://run.to/noicys
>
>
>Anti-racism movement: http://www.positive-youthfoundation.org
>Iraq Peace Pledge: http://www.peacepledge.org
>
>
>
>
>-------------------------------------------------------
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>
>  
>

RE: [Dev-C++] Can I handle 64 bits with unsigned long long int ?

[Ioannis V. <iv...@em...>]

Question about C99. That is a first! See below:



> -----Original Message-----
> From: dev...@li...=20
> [mailto:dev...@li...] On Behalf=20
> Of Roberto Ricardi
> Sent: Sunday, April 06, 2003 2:11 AM
> To: 'Dev-C++ -Users-List'
> Subject: [Dev-C++] Can I handle 64 bits with unsigned long long int ?
>=20
>=20
> Hi all,
>=20
> Can I handle 64 bits numbers with unsigned long long ?
>=20
> #include <stdio.h>
> #include <stdlib.h>
> #include <conio.h>
>=20
> unsigned long long int D0,D1 ;
>        =20
> int main(int argc, char *argv[])
> {
>   D0 =3D 0;
>   D1 =3D 0xffffffffffff; /*  I put first unsigned long int, compiler=20
> alerts about truncated number...) */
>   gotoxy(1,9);printf ("Num hexa : ");
>   scanf ("%x",&D0); /*can handle whatever up to 32 bits*/
>   gotoxy(1,11);printf ("Dec0: %lu\nDec1: %lu\n\n", D0, D1);
> =20
>   getchar();  getchar();
>   return 0;
> }
> /*
> Results:
>=20
> Dec0 : 4294967295 mean ok if I put just up to 0xffffffff  32bits
> Dec1 : 0  ??
> */
>=20
> Why is ever truncated in 32 bits, how can handle long long to=20
> get up to=20
> 64 bits numbers ?


unsigned long long is not guaranteed to be 64-bit. If you want an =
unsigned
integral type to be at least 64-bit, you have to do:


#include <stdint.h>

// ...

uint_least64_t D0, D1;

 // ...



which is a typedef of the closest to 64-bit type provided by platform
(closest from above, that is if unsigned long is 32 bit and unsigned =
long
long is 128 bit for example, the typedef will be of unsigned long long).


I read it straight from the standard. I do not know whether MINGW has
implemented it (and as far as I know these facilities are "optional", if =
the
platform doesn't support >=3D64 bit, will not have the above type =
naturally).


By the way, have you got any book regarding C99? If yes, can you please =
tell
me which?




Ioannis Vranos
=20
* Programming pages: http://www.noicys.freeurl.com
* Alternative URL: http://run.to/noicys


Anti-racism movement: http://www.positive-youthfoundation.org
Iraq Peace Pledge: http://www.peacepledge.org