dev-cpp-users

[<cg...@wo...>]

   >typedef void (classname::*funny)(void**); //I tried either void
   >
   >Well it depends on what arguments you want.

All them are void func(void**); The comment is continued in the next
line, I forgot taking into account the posible wrapping of the text.
Anyway I know the alternative I was citing is wrong.

  >funny *function; OR funny function[19];
  >
  >funny is a pointer to function type so if you want an array of
  >pointers to functions on the free store, you must use the "funny
  >*function" stuff.

funny *function stuff? Does it means say funny *function; and then
function = new funny[number]? I do it. (No spam)

   >Then inside another function:
   >int cuantos = rand() % 19;
   >(this->*function[cuantos])(NULL);

   >NULL is deprecated in C++. Also you forgot some parenthesis. You
should do:
   >
   >(this->*classname::function[cuantos])(0);
The parenthesis are there.


I didn't say all functions are private.
I used the modifications you pointed, still access violation, when 
calling the function.
...
cout << "Here!" << endl;
(this->*(classname::)cion[index])(param);
...
The output:
...
Here!
Program.exe has generated errors, it will be closed by windows, you'll 
have to restart it.
I tried some compiler options (-vtable-gc, and other) but no resul.