dev-cpp-users

RE: [Dev-C++] Linker :: Under the hood.

[Damien A <g_...@ho...>]

<html><div style='background-color:'><DIV class=RTE>
<P><BR>"ld (and therefore gcc) is sensitive about the order in which libraries and object<BR>files are specied on the command line. If libfoo.so depends on libbar.so, you<BR>must specify libfoo.so first (as counterintuitive as this may be). The reason is<BR>that ld keeps track only of unresolved symbols as it links. If libfoo.so and<BR>libbar.so depend on each other, one of the libraries will have to be specified<BR>twice (for example, -lfoo -lbar -lfoo)." -Programming Linux Games , pg 33<BR></P></DIV>
<DIV></DIV>----Original Message Follows---- 
<DIV></DIV>From: Siva Chandra &lt;siv...@ya...&gt; 
<DIV></DIV>To: dev...@li... 
<DIV></DIV>Subject: [Dev-C++] Linker :: Under the hood. 
<DIV></DIV>Date: Thu, 27 May 2004 08:47:17 -0700 (PDT) 
<DIV></DIV>
<P>MIME-Version: 1.0 </P>
<P>&nbsp;</P>
<DIV></DIV> 
<DIV></DIV>
<DIV></DIV>
<DIV></DIV>Hello all, 
<DIV></DIV>
<DIV></DIV>I am trying to understand how the linker goes about 
<DIV></DIV>doing its work. Say I have two linker options -lx and 
<DIV></DIV>-ly. If I pass them in the order -lx -ly the linker 
<DIV></DIV>seems to be doing its job fine. But if I pass -ly -lx 
<DIV></DIV>the linker spits hell a lot of undefined references at 
<DIV></DIV>me!! Can someone throw light on how the linker goes 
<DIV></DIV>about doing its work under the hood. Specifically, 
<DIV></DIV>what has the order got to do with it? 
<DIV></DIV>
<DIV></DIV>Siva Chandra 
<DIV></DIV>
<DIV></DIV>
<DIV></DIV>
<DIV></DIV>
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Re: [Dev-C++] Linker :: Under the hood.

[<wa...@wa...>]

On 27 May 2004 at 8:47, Siva Chandra wrote:

> 
> Hello all,
> 
> I am trying to understand how the linker goes about
> doing its work. Say I have two linker options -lx and
> -ly. If I pass them in the order -lx -ly the linker
> seems to be doing its job fine. But if I pass -ly -lx
> the linker spits hell a lot of undefined references at
> me!! Can someone throw light on how the linker goes
> about doing its work under the hood. Specifically,
> what has the order got to do with it?

The order shouldn't have anything to do with it.

Watson

RE: [Dev-C++] Linker :: Under the hood.

[<wa...@wa...>]

On 27 May 2004 at 12:00, Damien A wrote:

> 
> "ld (and therefore gcc) is sensitive about the order in which 
> libraries and object
> files are specied on the command line. If libfoo.so depends on 
> libbar.so, you
> must specify libfoo.so first (as counterintuitive as this may be). The
> reason is that ld keeps track only of unresolved symbols as it links.
> If libfoo.so and libbar.so depend on each other, one of the libraries
> will have to be specified twice (for example, -lfoo -lbar -lfoo)."
> -Programming Linux Games , pg 33 

Wow.

Interesting.  Thanks!

Watson

RE: [Dev-C++] Linker :: Under the hood.

[Siva C. <siv...@ya...>]

Hello all,

That was insightfull but also lead to another
question.
How do inline functions get linked?

Siva Chandra

--- Damien A <g_...@ho...> wrote:

---------------------------------


"ld (and therefore gcc) is sensitive about the order
in which libraries and object
files are specied on the command line. If libfoo.so
depends on libbar.so, you
must specify libfoo.so first (as counterintuitive as
this may be). The reason is
that ld keeps track only of unresolved symbols as it
links. If libfoo.so and
libbar.so depend on each other, one of the libraries
will have to be specified
twice (for example, -lfoo -lbar -lfoo)." -Programming
Linux Games , pg 33



	
		
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RE: [Dev-C++] Linker :: Under the hood.

[Per W. <pw...@ia...>]

When they are inlined, they are not linked. The compiler throws in
suitable assembler instructions directly.

When the inline function isn't inlined - because it is too large etc -
normally all source files that saw the inline declaration will get a
"common" code block with the function code.

The function then works as any other function with the extra feature
that the linker doesn't complain if multiple object files specifies the
function. The linker just selects one instance of the function and throws
away the other instances.

/Per W

On Fri, 28 May 2004, Siva Chandra wrote:

>
> Hello all,
>
> That was insightfull but also lead to another
> question.
> How do inline functions get linked?
>
> Siva Chandra
>
> --- Damien A <g_...@ho...> wrote:
>
> ---------------------------------
>
>
> "ld (and therefore gcc) is sensitive about the order
> in which libraries and object
> files are specied on the command line. If libfoo.so
> depends on libbar.so, you
> must specify libfoo.so first (as counterintuitive as
> this may be). The reason is
> that ld keeps track only of unresolved symbols as it
> links. If libfoo.so and
> libbar.so depend on each other, one of the libraries
> will have to be specified
> twice (for example, -lfoo -lbar -lfoo)." -Programming
> Linux Games , pg 33
>
>
>
>
>
> __________________________________
> Do you Yahoo!?
> Friends.  Fun.  Try the all-new Yahoo! Messenger.
> http://messenger.yahoo.com/
>
>
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