Small change to my last e-mail. After a little more reading I have come across the line
"A user-defined specialization looks like an ordinary template definition except that it must appear after its primary template."
In other words:
template <typename T>
T Operation(T value)
{ return value; }
template<> int Operation(int val)
{ return val; }
won't work but:
template <typename T>
T Operation(T value)
{ return value; }
template<> int Operation(int val)
{ return val; }
should work. My earlier comment about the template declaration and the function header being on different lines is just a sign of my lack of sleep.
Hope this helps some more
David McKen
----- Original Message -----
From: Pillati
To: dev...@li...
Sent: Sunday, October 05, 2003 6:20 PM
Subject: [Dev-C++] problems with template especialization
Hi!
I am trying to do with that a member method of a template class calls another method (with explicit specialization) that doesn't belong that class and it is defined in the same file. However, I obtain the following error: "multiple definition of 'int Operation(int)' ". Why doesn't this code work?
//Image.cpp
template <typename T>
T Operation(T value)
{ return value; }
template<> int Operation(int val)
{ return val; }
// member method of template class
template <typename Type>
void Image<Type>::setData()
{
int a;
a = Operation(10);
}
Raquel.
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