dev-cpp-users

[Dev-C++] I am new to C ++ and need some help

[J R <ray...@ya...>]

Now I'm sure to all you long time C++ ediotrs out there this question will be obvious but I just can't figure it out.  here goes.  I want a program that asks for your name and then I want it so if you enter   John   as your name it will say thanks and if you enter anything else it will say    Nope     I have tried and tried but to no avail.  Here is what I have

 

#include <iostream.h>
#include <stdlib.h>
int main()
{
unsigned short int name,john;
cout << "Please enter your name: ";
cin >> name;

 

if (name=john)
     cout << "\nThanks!\n";

else
     cout << "\nNope!\n";

system("PAUSE");
return 0;
}

 

As of now it says   thanks   no matter what.  I have tried and tried but nothing will work and I'm sure I did something stupid to make it not work.  If you could rewrite what I did wrong or just write a brand new code it would be greatly appreciated.

Thanks,

J



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Re: [Dev-C++] I am new to C ++ and need some help

[Matthew F. <fit...@ho...>]

Try this:

 include <iostream.h>

  int main (void)
{
 char John [5];
=20
cout << "please enter your name.." <<endl;

cin>>John;

if (John =3D=3D "John")
{
cout << "Thank you";
}
else (John !=3D "John")
{
cout << "Nope";
}

}
  ----- Original Message -----=20
  From: J R=20
  To: dev...@li...=20
  Sent: Sunday, December 10, 2000 10:50 AM
  Subject: [Dev-C++] I am new to C ++ and need some help


  Now I'm sure to all you long time C++ ediotrs out there this question =
will be obvious but I just can't figure it out.  here goes.  I want a =
program that asks for your name and then I want it so if you enter   =
John   as your name it will say thanks and if you enter anything else it =
will say    Nope     I have tried and tried but to no avail.  Here is =
what I have



  #include <iostream.h>
  #include <stdlib.h>
  int main()
  {
  unsigned short int name,john;
  cout << "Please enter your name: ";
  cin >> name;



  if (name=3Djohn)
       cout << "\nThanks!\n";

  else
       cout << "\nNope!\n";

  system("PAUSE");
  return 0;
  }



  As of now it says   thanks   no matter what.  I have tried and tried =
but nothing will work and I'm sure I did something stupid to make it not =
work.  If you could rewrite what I did wrong or just write a brand new =
code it would be greatly appreciated.

  Thanks,

  J





-------------------------------------------------------------------------=
-----
  Do You Yahoo!?
  Yahoo! Shopping - Thousands of Stores. Millions of Products.

RE: [Dev-C++] I am new to C ++ and need some help

[Ioannis V. <no...@ya...>]

A better and working version in C++ of this, is the following:

#include <iostream>
#include <string>

using namespace std;

int main()
{
string John;

cout << "Please enter your name.." <<endl;

cin>>John;

if (John == "John")
cout << "Thank you";
else
cout << "Nope";
return 0;

}


A corrected version of the original posting, so as to work is:

#include <iostream>

using namespace std;

int main ()
{
char John [5];
cout << "please enter your name.." <<endl;
cin>>John;
if (John == "John")
cout << "Thank you";
else
cout << "Nope";
}
  -----Original Message-----
  From: dev...@li...
[mailto:dev...@li...]On Behalf Of Matthew
FitzGerald
  Sent: Sunday, December 10, 2000 9:47 PM
  To: dev...@li...
  Subject: Re: [Dev-C++] I am new to C ++ and need some help


  Try this:

   include <iostream.h>

    int main (void)
  {
   char John [5];

  cout << "please enter your name.." <<endl;

  cin>>John;

  if (John == "John")
  {
  cout << "Thank you";
  }
  else (John != "John")
  {
  cout << "Nope";
  }

  }

[Dev-C++] Char safeguarding

[Jay S. <mys...@op...>]

syntax
--------
    do{
        cout<<"Enter two positive integers. ";
        cin>>x>>y;
    }while(x<=3D0||y<=3D0);
--------

If I enter a char while using that, (x and y declared as ints), it gives =
me an endless loop.  How would I do safeguard against a user entering an =
char? -.-

mystojay