printf("%.0f %",float_var); ERROR

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printf("%.0f %",float_var); ERROR

Forum: Bloodshed Software Forum

Creator: Nobody/Anonymous

Created: 2003-02-16

Updated: 2012-09-26

Nobody/Anonymous - 2003-02-16

someone knows why don't show the last %?

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- Nobody/Anonymous - 2003-02-16
  
  why dont people search google beofer asking such a simple question...
  
  Zero Valintine
  
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- Curtis Sutter - 2003-02-17
  
  I believe you will need a \ infornt of the % since the % is something important. Kinda like having \" \' \\ when showing those characters.
  
  Curtis
  
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- Ondrej Majerech - 2003-02-17
  
  Jes, but not \, but another % so - printf ("%.0f %%", float);
  
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- Curtis Sutter - 2003-02-18
  
  Ok, I am just always using C++ with the \ excape char and not C with the % excape char. Thanks for letting me know. I will try to remember in the future.
  
  Curtis
  
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