passing structs to functions

[Nobody/Anonymous]

I have an array of structs, example:
struct mystruct
{
int blah;
double blahblah;
};

mystruct mylist[10];

void myfunction(mystruct mylist[]);
{
//function
}

it gives me an error at the '{' after void. what is wrong with my code? sorry for not giving a good example.

[Nobody/Anonymous]

Remove that semicolon at the end of:

void myfunction(mystruct mylist[]);

Derek

[Nobody/Anonymous]

Let me take a look at my book when I get to work, but I thought the notation for using an array as a function argument was something like

void myfunction(mystruct mylist[], int n)

where n is the number of elements in the array.   But it is early in the morning and I am pretty dim to start with.

The earlier note on teh semicolon is also correct, you have done the classic error of creating an empty function, i.e.

void myfunction(mystruct mylist[]);
                                                   ^
This is your function, the nothing between ) and ;

Common mistake.  Done it a lot, will do it some more.

Wayne

[j@ck_]

Hello,
I have this simple program to offer. Hope it can help.

#include <cstdlib>
#include <iomanip> //..setprecision ect
#include <iostream>

   using namespace std;

struct alphaDom
{
  double st_cap;
  double st_han;
  double st_kop;

  double networkNumber();                 
};

int main()
{
  cout.setf(ios::fixed);
 
  alphaDom NalphaDom = { 103.498, 206.998, 302.986 };
   alphaDom* palphaDom = &NalphaDom;                    
    cout << endl
       << "networkNumber is " << setprecision(3) <<palphaDom->networkNumber() << endl << endl;

  system("PAUSE");
  return 0;
}

double alphaDom::networkNumber()
{
  return st_cap * st_han * st_kop;
}