How to deal with the return of a function?

[Nobody/Anonymous]

Im sorry, my english writting is horrible, please read the above and you will understand what i am asking you help on:
int x; //This is declared somewhere, and other functions set its value.

int function a() { //This is called by mainFunction.
if x==1 {
return 0;
}
else {
return 1;
}
}

int masterFunction() {
a();
//if a() returns 0 do this
//else do that
}

How do i do what i wrtote in the commented lines of mainFunction?
Thanks!

[Nobody/Anonymous]

Hi,

1. Function definition is like this:
declaration-specifiers function-name (parameter-type-list)
declaration-list<opt>
compound-statement

so no keyword "function".

2. If statement:
if (expression) statement

so expression must be between parentheses.

3. Return with expression:
expression is returned to caller as value of function call expression

so you either write if (a () == 0) do this or assign a() to variable.

tkorrovi

[Derek Baker]

int x; //This is declared somewhere, and other functions set its value.

int a() { //This is called by mainFunction.
if (x==1) {
return 0;
}
else {
return 1;
}
}

int masterFunction() {
if (a() == 0){
//do this
}
else{

cout << "not zero" << endl;
}
}

Derek