Pointing at a Place

[9v1cl0]

I have been working with pointers, and I am curious is it possible to add one (in hex) to a pointer so that if the location of the pointer is displayed I would get 0x445021 instead of 0x445020. I know that by saying *pa++ and the original address is 0x445020 i would get 0x445028. Or is it possible to force a variable to be at a certain location?
Thanks

[Anonymous]

Pointer arithmetic works in units determined by teh size of teh object to which it points.

Your point about *pa++ id not right, you dereferncing the pointer, so it would incremented the value pointerd to. If you meant pa++, the statement is only true if sizeof(pa) = 8 (a long long for example). If pa were a pointer to a char, the address increment would indeed be 1.

Consider teh following code. Note how the address after ++ is determined by the pointer type.
int main()
{
int array[] = { 0x11223344,0x55667788,3,4,5,6,7,8,9 };
int pa = array ;
char pb = (char*)array ;

printf( "%p, %p\n", pa, pb ) ;
printf( "%X, %X\n\n", *pa, *pb ) ;
pa++ ;
pb++ ;
printf( "%p, %p\n", pa, pb ) ;
printf( "%X, %X\n", *pa, *pb ) ;

system("PAUSE");
return 0;

}