encrypting a string

[anonymous nobody]

include <cstdlib>

include <cstdio>

include <cstring>

define atoc static_cast<char>

define ctoa static_cast<int>

void crypt(int s,char a)
{
int i;
for(i=0;i<s;i++)
{
if(ctoa(a[i])<126)
{
a[i]=atoc(rand())%130;
}
else
{
a[i]=atoc(ctoa(a[i])+1);
}
}
for(i=s;i<s+50;i++)
{
delete(&a[i]);
}
}
int main(int argc, char argv[])
{
char i[10];
strcpy(i,"");
printf("Enter 10 characters.\n");
scanf("%s",i);
crypt(10,i);
printf("\n%s\n",i);
system("PAUSE");
return 0;
}

This code is supposed to take a string with a length of 10 and encrypt it using ASCII numbers. It works fine except for one thing: the printed string is 15 characters long, instead of 10. I have no ideas; any help?

-JM

[anonymous nobody]

Ah... I've solved the problem. I've always thought char a[10] made an array with 10 elements but it actually makes 11. Thus:

include <cstdlib>

include <cstdio>

include <cstring>

define atoc static_cast<char>

define ctoa static_cast<int>

void crypt(int s,char a)
{
int i;
for(i=0;i<s;i++)
{
if(ctoa(a[i])<126)
{
a[i]=atoc(rand())%130;
}
else
{
a[i]=atoc(ctoa(a[i])+1);
}
}
for(i=s;i<s+50;i++)
{
delete(&a[i]);
}
}
int main(int argc, char argv[])
{
char i[9];
strcpy(i,"");
printf("Enter 10 characters.\n");
scanf("%s",i);
crypt(10,i);
printf("\n%s\n",i);
system("PAUSE");
return 0;
}

produces the correct result.