Incorrect use of combinatorials could be flagged

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#5 Incorrect use of combinatorials could be flagged

Status: open

Owner: nobody

Labels: CDL Language (2)

Priority: 5

Updated: 2008-03-20

Created: 2008-03-20

Creator: Anonymous

Private: No

CDL could flag intermediate use of a combinatorial.

e.g.

x=1;
if (x==1) {y=1;}
x=3;

What happens?

Is it supposed to be x=1;x=3; so x as a signal has the value 3?
Or is it supposed to operate on the intermediate value?