Call new type method

[Fernando L. <fer...@gm...>]

Two questions ...
a) How can I pass a pointer to a new type object?
b) Can I access methods from this pointer?

Like in

class Block : Public PythonClass<Block> {
     Block *parent;
     Block(Py::PythonClassInstance *self, Py::Tuple &args, Py::Dict &kwds):
     : Py::PythonClass< Block >::PythonClass( self, args, kwds )
    {
        args.verify_length(1);
       // Is this possible ??? or something like this
        parent  = (Block*) args[0];
    }
...
...
    Py::Object getFullName( void )
    {
        std::string r = "";
        if( ! parent->isNone() )
            r += Py::String( parent->getFullName()).as_std_string( "utf-8" )
+ ".";

/* I want to access parent's methods directly to avoid the overload of
calling
   callMemberFunction("getFullName") and many others that I need.
   Is it possible?
   Is callMemberFunction restricted to the exposed ones?
*/
        r += name.as_std_string( "utf-8" );
        return Py::String(r);
    }
...
...
};

-- 
Fernando Libonati
fernando.libonati at gmail.com