Re: [chiPHPug-discuss] troublesome PHP behavior

[Wilfried S. <ws...@de...>]

http://us3.php.net/explode:

"If delimiter  contains a value that is not contained in string , then  
explode() will return an array containing string."


If you're using explode(), you're probably expecting an array. Seems  
normal to me..


On Feb 20, 2009, at 15:00 , Arlo Leach wrote:

> Hi folks,
>
> Consider the following PHP code, which explodes an empty string:
>
>    $string = "";
>    $array = explode("|", $string);
>    print_r($array);
>    print "Length: ".count($array);
>
> I would expect this to output an empty array:
>
>    Array ( ) Length: 0
>
> But it actually outputs:
>
>    Array ( [0] => ) Length: 1
>
> Does anyone else find this odd? It has bitten me a few times lately,  
> when I
> test the existence of data with a count(), or try to process data  
> with a FOR
> loop. I end up writing this a lot to get the expected results:
>
>    $array = ($string) ? explode(",", $string) : array() ;
>
> I was considering logging a bug report but wondered what your  
> thoughts were.
>
> Cheers,
> -Arlo
>
> _______________________________
>
> Arlo Leach
> 773.769.6106
> http://arlomedia.com
>
>
>
>
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