Re: [chiPHPug-discuss] troublesome PHP behavior

[Ryan G. <sok...@gm...>]

If you explode an empty string, it makes sense to have a one element
array, which consists of that same empty string.

If you try count(array("")) , you will get a result of one, as an
empty string is still an array element.
There are a lot of different options for locating characters inside of
a string, I'd probably go with strrpos.

On Fri, Feb 20, 2009 at 1:00 PM, Arlo Leach <ar...@ar...> wrote:
> Hi folks,
>
> Consider the following PHP code, which explodes an empty string:
>
>    $string = "";
>    $array = explode("|", $string);
>    print_r($array);
>    print "Length: ".count($array);
>
> I would expect this to output an empty array:
>
>    Array ( ) Length: 0
>
> But it actually outputs:
>
>    Array ( [0] => ) Length: 1
>
> Does anyone else find this odd? It has bitten me a few times lately, when I
> test the existence of data with a count(), or try to process data with a FOR
> loop. I end up writing this a lot to get the expected results:
>
>    $array = ($string) ? explode(",", $string) : array() ;
>
> I was considering logging a bug report but wondered what your thoughts were.
>
> Cheers,
> -Arlo
>
> _______________________________
>
> Arlo Leach
> 773.769.6106
> http://arlomedia.com
>
>
>
>
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