Re: [chiPHPug-discuss] troublesome PHP behavior

[Trevor O. <tr...@gm...>]

It seems like reasonable behavior to me.
An empty string is a valid array value for explode. For example, if you
exploded "||", it should return three empty strings.
And from php.net:
Return Values

If *delimiter* is an empty string (""), *explode()* will return *FALSE*. If
*delimiter* contains a value that is not contained in *string* , then *
explode()* will return an array containing *string* .



2009/2/20 Arlo Leach <ar...@ar...>

> Hi folks,
>
> Consider the following PHP code, which explodes an empty string:
>
>    $string = "";
>    $array = explode("|", $string);
>    print_r($array);
>    print "Length: ".count($array);
>
> I would expect this to output an empty array:
>
>    Array ( ) Length: 0
>
> But it actually outputs:
>
>    Array ( [0] => ) Length: 1
>
> Does anyone else find this odd? It has bitten me a few times lately, when I
> test the existence of data with a count(), or try to process data with a
> FOR
> loop. I end up writing this a lot to get the expected results:
>
>    $array = ($string) ? explode(",", $string) : array() ;
>
> I was considering logging a bug report but wondered what your thoughts
> were.
>
> Cheers,
> -Arlo
>
> _______________________________
>
> Arlo Leach
> 773.769.6106
> http://arlomedia.com
>
>
>
>
>
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-- 
-Trevor Oldak