Re: [chiPHPug-discuss] troublesome PHP behavior

[Michael L. <mla...@ca...>]

Arlo,

I've run into that and though it's annoying, I think it's part of the
"desired behavior" for the function.

>From php.net/explode

"If delimiter contains a value that is not contained in string , then
explode() will return an array containing string"

So, since your string doesn't contain a "|" is returns the "array" of an
empty string. Make sense? 

-----Original Message-----
From: Arlo Leach [mailto:ar...@ar...] 
Sent: Friday, February 20, 2009 3:00 PM
To: Chicago PHP User Group
Subject: [chiPHPug-discuss] troublesome PHP behavior

Hi folks,

Consider the following PHP code, which explodes an empty string:

    $string = "";
    $array = explode("|", $string);
    print_r($array);
    print "Length: ".count($array);

I would expect this to output an empty array:

    Array ( ) Length: 0

But it actually outputs:

    Array ( [0] => ) Length: 1

Does anyone else find this odd? It has bitten me a few times lately,
when I test the existence of data with a count(), or try to process data
with a FOR loop. I end up writing this a lot to get the expected
results:

    $array = ($string) ? explode(",", $string) : array() ;

I was considering logging a bug report but wondered what your thoughts
were.

Cheers,
-Arlo

_______________________________

Arlo Leach
773.769.6106
http://arlomedia.com




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