[cgiwrap-users] a php-cgiwrap method?

[Jeff B. <soi...@sg...>]

I've come up with a simple method of using the new php-cgiwrap in such a way
to wrap php in such a way that the scripts can be put in the main web tree..
this is what i do:

I compile cgiwrap twice... the first time for cgi scripts and the second
time for php... like this:

1) for cgi

#./configure \
> --with-httpd-user=apache \
> --with-install-dir=/path-to-root-apache/cgi-sys \
# make
# make install

2) then i recompile for php (php was compiled as binary into /usr/local/bin
with --enable-discard-path)

# make clean
#./configure \
> --with-httpd-user=apache \
> --with-install-dir=/tmp \
> --with-cgi-dir=public_html \
> --with-php=/usr/local/bin/php \
> --with-php-cgiwrap
# make
# make install

3) then I copy the cgiwrap executable compile for php into the cgi-sys
folder as 'php-cgiwrap' and link php-cgiwrapd to it:

# cp /tmp/cgiwrap /path-to-root-apache/cgi-sys/php-cgiwrap
# ln php-cgiwrap php-cgiwrapd

4) then in each of  my vhost defs i add these directives

AddHandler php-cgiwrap .php
Action php-cgiwrap /cgi-sys/php-cgiwrap/USERNAME

where USERNAME is the username of the vhost owner. and also note that
'cgi-sys' is my new system "cgi-bin"... i just replaced the cgi-bin stuff
for the main server in httpd.conf with cgi-sys.

What this does is allow them to put their php scripts in the web tree and
still have them wrapped without the #!/usr/local/bin/php (thanks Piotr and
Nathan for building this in) line.

As I'm definitely no expert in this I have no idea if there is a more
elegant way to do this.  If this is the best way then I wish we could build
it into the compile sequence with a new compile option of:

--with-php-script-dir =

that would define the php script path separately from the cgi scripts.  But
it would have to create two executables... cgiwrap and php-cgiwap instead of
just the one cgiwrap...

If it's not then would you please clue me in?

Thanks,

Jeff