[Bashdb-devel] bashdb problem when 'set -u' is used.

[Peng Y. <pen...@gm...>]

Hi,

I have used 'set -u' in my bash script. But it seems that bashdb is
not friendly with 'set -u'. Can somebody fix this in future versions
of bashdb?

Thanks,
Peng



$ cat echo.sh
#!/bin/bash

set -u

echo Hello

$ bashdb echo.sh
Bourne-Again Shell Debugger, release bash-3.1-0.06
Copyright 2002, 2003, 2004, 2006 Rocky Bernstein
This is free software, covered by the GNU General Public License, and you are
welcome to change it and/or distribute copies of it under certain conditions.

(/tmp/echo.sh:3):
3:      set -u
bashdb<0> n
/usr/share/bashdb/dbg-fns.inc: line 63: _Dbg_file_cmd_StmpSechoDsh:
unbound variable
/usr/share/bashdb/dbg-fns.inc: line 96: _Dbg_action_StmpSechoDsh[5]:
unbound variable
/usr/share/bashdb/dbg-fns.inc: line 96: _Dbg_brkpt_StmpSechoDsh[5]:
unbound variable
(/tmp/echo.sh:5):
5:      echo Hello
bashdb<1> n
Hello
/usr/share/bashdb/dbg-fns.inc: line 63: _Dbg_file_cmd_SusrSbinSbashdb:
unbound variable
/usr/share/bashdb/dbg-fns.inc: line 96:
_Dbg_action_SusrSbinSbashdb[285]: unbound variable
/usr/share/bashdb/dbg-fns.inc: line 96:
_Dbg_brkpt_SusrSbinSbashdb[285]: unbound variable
/usr/share/bashdb/dbg-fns.inc: line 63: _Dbg_read_SusrSbinSbashdb:
unbound variable
/usr/share/bashdb/dbg-fns.inc: line 63: _Dbg_file_cmd_SusrSbinSbashdb:
unbound variable
/usr/share/bashdb/dbg-fns.inc: line 96:
_Dbg_source_SusrSbinSbashdb[285]: unbound variable
(/usr/bin/bashdb:285):
285:
bashdb<2> q
/usr/share/bashdb/dbg-sig.inc: line 271: BASHDB_RESTART_COMMAND:
unbound variable