[Bashdb-devel] Multiline command substitution in subshell bug

[Mikael A. <sn...@te...>]

It's nothing serious but a bit confusing. The shell-script below gives the 
following output in bashdb. 
A clarification: my bash executable is renamed to bashdb and the bashdb script 
to bash-debugger.


------- output
snikkt> -bashdb --debugger multiline.sh
(multiline.sh:6):
6:      )`
bashdb<0> s
(multiline.sh:7):
7:      echo $s #This line should not be displayed until later
bashdb<((1))> s
(multiline.sh:8):
8:      #Didn't expect to see me ?
bashdb<((2))> s
(multiline.sh:9):
9:      #And not me either ?
bashdb<((3))> s
(multiline.sh:7):
7:      echo $s #This line should not be displayed until later
bashdb<4> s
This is not visible while debugging
(multiline.sh:10):
10:
bashdb<5> s
Debugged program terminated normally. Use q to quit or R to restart.
bashdb<6> q

----------- script
#!/bin/bash
s=`(
        echo This is
        echo not visible
        echo while debugging
)`
echo $s #This line should not be displayed until later
#Didn't expect to see me ?
#And not me either ?