It's nothing serious but a bit confusing. The shell-script below gives the
following output in bashdb.
A clarification: my bash executable is renamed to bashdb and the bashdb script
to bash-debugger.
------- output
snikkt> -bashdb --debugger multiline.sh
(multiline.sh:6):
6: )`
bashdb<0> s
(multiline.sh:7):
7: echo $s #This line should not be displayed until later
bashdb<((1))> s
(multiline.sh:8):
8: #Didn't expect to see me ?
bashdb<((2))> s
(multiline.sh:9):
9: #And not me either ?
bashdb<((3))> s
(multiline.sh:7):
7: echo $s #This line should not be displayed until later
bashdb<4> s
This is not visible while debugging
(multiline.sh:10):
10:
bashdb<5> s
Debugged program terminated normally. Use q to quit or R to restart.
bashdb<6> q
----------- script
#!/bin/bash
s=`(
echo This is
echo not visible
echo while debugging
)`
echo $s #This line should not be displayed until later
#Didn't expect to see me ?
#And not me either ?
|
