Re: [Asterisk-java-users] Who is firing the propertyChange?

[Martin S. <ma...@be...>]

Hi Chuck,

The propertyChangeEvent has a "source" that you want to be the
AsteriskChannel class. For example:

 public void propertyChange(PropertyChangeEvent propertyChangeEvent)
    {
        Object src =3D propertyChangeEvent.getSource();
        if(!(src instanceof AsteriskChannel) || src =3D=3D null)
            return;

        AsteriskChannel channel =3D (AsteriskChannel)src;

	   // do some stuff
	}

If I only want channel events, I typically check that the source is what
I expect -- as sometimes I will (ab)use the property change methods with
my own objects.

Take care,

Martin Smith, Systems Developer
ma...@be...
Bureau of Economic and Business Research
University of Florida
(352) 392-0171 Ext. 221=20

=20

> -----Original Message-----
> From: ast...@li...=20
> [mailto:ast...@li...] On=20
> Behalf Of CHUCK SYPERSKI
> Sent: Thursday, July 19, 2007 8:05 AM
> To: ast...@li...
> Subject: [Asterisk-java-users] Who is firing the propertyChange?
>=20
> I am sorry this may be a simple questions but I am stuggling=20
> to figure it out.  I have a multi threaded app that is using=20
> the live classes.  It makes new calls and then monitors thier=20
> progress towards completion.  The problem is when the=20
> propertyChange event fires how can I identify which channel=20
> or for example which Channel the ChannelState=20
> "propertyChange" is refering too?  Below is a piece of code=20
> to show what I am talking about. =20
>=20
> Thanks again, this list has been very helpful!
>=20
> Each thread that runs has this method, but it seems that the=20
> events for all calls broadcast to all propertyChange functions.
>=20
> 	public void propertyChange(PropertyChangeEvent=20
> propertyChangeEvent)
> 	{
> 		try
> 		{
> 			if ( propertyChangeEvent.getNewValue()=20
> instanceof ChannelState )
> 			{
> 				ChannelState c =3D=20
> (ChannelState)(propertyChangeEvent.getNewValue());
> 				handleStateChange( c );
> 			}
> 	=09
> 		}
> 		catch( Exception e )
> 		{
> 			lg( e.getMessage() );
> 			e.printStackTrace() ;
> 		}
> 	}
>=20
> Thanks,
> Chuck Syperski
>=20
>=20
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>=20