[Asterisk-java-users] Origination Success, and Dispositon Failure

[Jason W. <ja...@cl...>]

Hello,

I am using asterisk java to send origination requests to asterisk server.

I test to see if I have received "Success" in the originationresponse. 
On some calls, I do receive a Success, but the disposition in the CDR 
reports shows "Failure" because the line is busy. I pretty sure, please 
correct me if wrong, that Origination Response is not the same as 
Disposition as reported by asterisk.

Here's my problem. I'm using IAX so I don't know the channel that will 
be used for the call until the call is answered.

Here's what happens in normal opperation:

1. origination action sent to Asterisk server with callMap of variables 
(one variable is callRecordId, which identifies this call in my database)
2. asterisk originates the call and returns success
3. call is answered, userdefined event is fired, reporting two things... 
the callRecordId and the channel, so that my origination program can now 
respond to events generated for this channel. Whenever I receive events 
from asterisk, I check the channel, and look in my 'channels' map to see 
which recordid this channel is servicing. Then I know what call the 
event is referencing.
4. so now when I receive a hangup event, which includes channel, I know 
which call was hungup.

PROBLEM:
1. when the line is 'busy' or basically anything besides 'Answered', I 
don't enter the extensions and therefor the channel doesn't get 
registered, and I don't know that the call has failed in my origination 
program.

I do receive a ''hangup" event, but I don't know which origination 
request it belongs to because the channel never got registered, linked 
to a callrecordid.

when I do an originate, remember that I pass a 'callmap' of variables 
about the call... If I could override the hangup event, to tell me more 
than just channel... like 'recordid' also from my callmap, then I could 
parse this event and problem would be solved.

Before I start changing asterisk hangup event code, is their a better, 
simpler way to solve this problem?

Jason