From: Stefan R. <sr...@re...> - 2005-12-12 10:42:51
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please show me what call.toString() returns and which version of asterisk you use. thx stefan Jan du Toit schrieb: > Stefan Reuter wrote: > >>>My question is how do you extract this generated random number, so that >>>one can succesfully hangup a channel using HangupAction? >>> >>> >>The easy solution is to use DefaultAsteriskManager to originate the >>call. Its originateCall method returns a Call object that contains the >>channel name. >>An other option is to listen for OriginateSuccess events (see the >>HelloEvents example on how to do that) and extract the channel name from >>that event. >> >>=Stefan >> >> > I have the following piece of code: > .... > Originate org; > Call call; > managerConnection.login(); > > org = new Originate(); > org.setChannel("SIP/Jan"); > org.setContext("sgs"); > org.setExten(getExtensionNumber()); > org.setPriority(new Integer(1)); > //set time before call must be picked up. > org.setTimeout(new Long(30000)); > > call = this.asteriskManager.originateCall(org); > str += "CALL:"+call.getChannel()+"\n"; //this method returns > null. > > managerConnection.logoff(); > .... > > The originateCall method is passed an Originate object configured with > all the needed info. The DefaultAsteriskManager's originateCall method > returns a Call object from which you can extract the channel name from > the call, but this method when executed returns null. > > The call is succesfully made and answered. > > I'm still not getting to the channel name of the form > "SIP/Jan-uniquerandom#" in order to sucesfully hangup. > > > > -- > ============================ > Jan Gerryt du Toit > Software Developer > DecisionWorx > Cell : +27721769536 > ============================ > |