Re: [Asterisk-java-users] "MonitorAction" always 'Exceeds TimeOut'

[Jose B. <pe...@gm...>]

Oops! I receive "timeout exceed" exception for every Action. :(((

Maybe my code is not properly written to handle Actions and their
responsess.....

When I receive a specfic event I want to send an Action, but everytime I
"sendAction" it is a "timeout" exception.

I'm running my program as:

 public void run() throws IOException, AuthenticationFailedException,
          TimeoutException, InterruptedException {

   managerConnection.addEventListener(this);
   managerConnection.login();

   while (running) {
      Thread.sleep(5000);
   }

   managerConnection.logoff();
    }

 @Override
 public void *onManagerEvent(ManagerEvent event)* {

   // If event is NewExtenEvent...
   if (event.getClass() == NewExtenEvent.class) {
       handleEvent((NewExtenEvent) event);
   }
   // If event is NewChannel...
   else if ((event.getClass() == NewChannelEvent.class)) {
      handleEvent((NewChannelEvent) event);
   }
 }

Sometimes I "sendAction" in NewExtenEvent (with the code sent in the
previous email).




On 2 January 2014 17:01, Jose Baez <pe...@gm...> wrote:

> Hi!
>
> I've been struggling a bit with
> asterisk-java-1.0.0.CI-20140101.jar (January 1st, 2014) and Asterisk v11.5
>
> Whenever I run *"MonitorAction"* Asterisk-java replies with "TimeOut
> Exceed" exception, but Asterisk is recording OK.
> Same exception happens with "StopMonitor".
>
>   try {
>       managerConnection.sendAction(*new MonitorAction*(channel, filename,
> "WAV", true));
>
>       // Forcing a timeout still pops exception.
>       //managerConnection.sendAction(*new MonitorAction*(channel,
> filename, "WAV", true), 1000);
>
>   } catch (IOException ex) {
>       System.out.println(ex);
>   } catch (TimeoutException ex) {
>       System.out.println(ex);
>   } catch (IllegalArgumentException ex) {
>       System.out.println(ex);
>   } catch (IllegalStateException ex) {
>       System.out.println(ex);
>   }
>
>
> Any idea?
>