Re: [Arsperl-users] Need Help: Qualification String "LIKE"

[Thilo S. <thi...@ap...>]

Use the field ID instead of "User Ident", e.g.

'536870912' LIKE "%-N-%"


Regards,
Thilo Stapff





On 08.07.2010 17:05, Chinh Do wrote:
> I need to search all fields that have this string "-N-" in the middle,
> for examples, "123-N-abc" and "4759ABC-N-Bill". Using Oracle SQL, I can
> code "...fieldname LIKE '%-N-%' ". I tried "my $qual1 = "'User Ident'
> LIKE \"%-N-%\"" but it does not work.
> How do I code the qualification string using ARSPerl to get the same
> result as using "LIKE"?
> Thank you,
> Chinh.
>
>
>
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