[Arsperl-users] [RESOLVED]Re: ars_SetEntry usage when updating remedy incident
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jeffmurphy
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From: Ravi <ra...@co...> - 2008-04-27 15:31:10
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thanks. What also worked is by passing an array instead of a string.
ars_SetEntry($ctrl, $schema, $record, 0, @updRemString)
Ravi
jeff murphy wrote:
>
> On Apr 26, 2008, at 8:13 AM, Ravi wrote:
>> ars_SetEntry($ctrl, $schema, $record, 0, 536871244, 3) || die
>> "ars_SetEntry(User): $ars_errstr";
>>
>> But if I set a variable $updRemString and run the ars_SetEntry, it gives
>> me an error as shown below
>> $updRemString = "536871244, 3"
>> ars_SetEntry($ctrl, $schema, $record, 0, $updRemString) || die
>> "ars_SetEntry(User): $ars_errstr";
>>
>
>
> The first (working) line is:
>
> ars_SetEntry($ctrl, $schema, $record, 0, 536871244, 3)
>
> The second (nonworking) lis:
>
> ars_SetEntry($ctrl, $schema, $record, 0, $updRemString)
>
> which is equivalent to:
>
> ars_SetEntry($ctrl, $schema, $record, 0, "536871244, 3");
>
> In other words, you are only passing five, instead of six, parameters.
> The final parameter is
> a single string parameter, instead of being two numeric parameters.
> You could try this:
>
> ars_SetEntry($ctrl, $schema, $record, 0, split(",", $updRemString) );
>
>
>
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