Re: [Arsperl-users] ars_SetEntry usage when updating remedy incident

[jeff m. <jcm...@je...>]

On Apr 26, 2008, at 8:13 AM, Ravi wrote:
> ars_SetEntry($ctrl, $schema, $record, 0, 536871244, 3) || die
> "ars_SetEntry(User): $ars_errstr";
>
> But if I set a variable $updRemString and run the ars_SetEntry, it  
> gives
> me an error as shown below
> $updRemString = "536871244, 3"
> ars_SetEntry($ctrl, $schema, $record, 0, $updRemString) || die
> "ars_SetEntry(User): $ars_errstr";
>


The first (working) line is:

ars_SetEntry($ctrl, $schema, $record, 0, 536871244, 3)

The second (nonworking) lis:

ars_SetEntry($ctrl, $schema, $record, 0, $updRemString)

which is equivalent to:

ars_SetEntry($ctrl, $schema, $record, 0, "536871244, 3");

In other words, you are only passing five, instead of six, parameters.  
The final parameter is
a single string parameter, instead of being two numeric parameters.  
You could try this:

ars_SetEntry($ctrl, $schema, $record, 0, split(",", $updRemString) );