Re: [Arsperl-users] Inserting a date in ARSPerl
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jeffmurphy
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From: Thilo S. <thi...@ap...> - 2007-10-17 17:03:56
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Unfortunately, date fields (unlike date/time fields) are only supported
since ARSperl version 1.90
The value has to be an integer which can be computed from an epoch
timestamp by
int( $epoch_time / 86400 ) + 2440588
Regards,
Thilo Stapff
Pittman, Timothy wrote:
> I have been having considerable difficulty trying to use ARSPerl to
> create an entry with a date. My web page is prompting the user to enter
> a date, which I'm assuming will be in the format mm/dd/yyyy. I am using
> the perl module ParseDate to attempt to figure out what they enter. In
> any case, I need to convert this user-entered value into some format
> that ars_CreateEntry can deal with. My code does this:
>
> ($entryId = ars_CreateEntry($ctrl, $shopSchema,
> $sf{"Description"}, $details,
> ... various fields you don't care about...
> $sf{"Date Required"}, "$date1",
> ... more fields...
> $sf{"Status"}, "Submitted"))
> or print "\n<p>[ERROR]\tCould not add shop order due to
> $ars_errstr<b><br>\n";
>
> I have tried numerous ways of formatting the date field $date1 above to
> attempt to get it to shop up in the proper format in Remedy. I have
> tried numerous variations of the following:
> A string (i.e. "10/17/2007")
> An integer (converted via timelocal and others to epoch time)
>
> I either end up with the date 1/1/9999 or 1/1/4713 B.C. in my date
> field. I have searched everywhere on the net that I can find and nothing
> has helped. Does anyone know what to do to a user-entered date to make
> ars_CreateEntry accept it properly?
>
> This is running on a Win2K server with ARSPerl 1.82 against a Remedy 6.0
> system on Oracle.
>
> Thanks, Tim
>
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