From: pito <pi...@vo...> - 2010-09-01 12:19:44
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Hi, here is a very simple integration (no special method applied) for testing f+ and f*. It integrates y=x^3 from A to B. Currently A=-B (e.g. -1 to +1) thus the result shall be zero. Still thinking on N in the loop (:-)). Pito ------------------------- marker -testadd \ very simple integration to test float add, sub \ needs float constants \ INTEGRAL from A to B of the function Y=X^3 \ A=-B, So the result shall be 0 -1 s>f fconstant _-1 0 s>f fconstant _0 \ FROM A TO B -1 s>f fconstant A A _-1 f* fconstant B 300 constant N B A f- N s>f f/ fconstant delta fvariable INTG fvariable X fvariable Y variable NLoop : p6 _1e6 f* f>d d. ." .1e-6 " ; : p3 _1e3 f* f>d d. ." .1e-3 " ; : Y=X^3 fdup fdup f* f* ; : Y=X^2 fdup f* ; : print_INTG INTG f@ p3 ; : INTEGRAL A X f! _0 INTG f! N 1 + NLoop ! NLoop @ 0 do X f@ Y=X^3 Y f! \ print X, Y cr cr X f@ ." X=" p6 cr Y f@ ." Y=" p3 Y f@ INTG f@ f+ INTG f! X f@ delta f+ X f! \ print cr INTG f@ ." INTG=" p3 loop \ print cr cr ." RESULT=" print_INTG ; ----------------- Ex: ..... X=1000004 .1e-6 Y=1000 .1e-3 INTG=1 .1e-3 RESULT=1 .1e-3 ok > |