From: <an...@ki...> - 2010-05-13 16:34:37
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Looking at the quote below. Are we actually saying here that the top 64k is not accessible then on a 128k device ?? That the memory is arranged in Amforth in words (ie 16 bit) ?? Or that it is paged and therefore takes a bit more time to access ?? Sorry for being a bit dim..... Cheers Andy kirby Matthias Trute wrote: > [1] The 128KB flash are seen as 64KWords to fit into the 16bit address > range, and there are a few other instructions to use. And finally the big > atmegas are slightly slower when accessing the flash since they need > to execute more instructions. But thats all hidden inside a few macros. |