Nina Jeliazkova - 2016-03-30

This is still a valid issue

O=C1OC3=CC=CC=C3(C(O)C1C(C=2C=CC=CC=2)CC(=O)C)
6 tautomers

C3=C(C(C1=C(OC2=C(C1=O)C=CC=C2)O)CC(=O)C)C=CC=C3
9 tautomers