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#104 make SDCC a "multi-call" binary

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nobody
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1
2005-05-18
2005-05-18
No

would be nice if SDCC behaved a little like busybox and
automatically set its target port if it's called with a
different name?

So you could do something like:
ln -s /usr/local/bin/sdcc /usr/local/bin/ds390-sdcc
ln -s /usr/local/bin/sdcc /usr/local/bin/picxx-sdcc
ln -s /usr/local/bin/sdcc /usr/local/bin/hc08-sdcc
ln -s /usr/local/bin/sdcc /usr/local/bin/z80-sdcc

and SDCC would behave as if its -m option had been set
(prefixing the port name as gcc does) when it's called
f.e. as z80-sdcc

Discussion

  • Frieder Ferlemann

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    user_id=589052

    Hi,
    as long as Sourceforge's CVS is down I might as well add a
    patch.
    It adds a dependency on <libgen.h>. I have no clue about the
    implications of this dependency, so maybe it's not bad to
    submit it as a patch anyway.

     
  • Frieder Ferlemann

     
  • Frieder Ferlemann

    in svn revision #5473.

    Leaving the request open for now because I couldn't check with Windows and because "make install" does not set the links (do we want to?)

     
  • Borut Ražem

    Borut Ražem - 2009-07-18

    WIN32 fix in svn revision #5474.

    Borut

     
  • Borut Ražem

    Borut Ražem - 2009-07-18

    Frieder,

    in the current implementation the target defined in the application name has higher priority then -m command line option:

    "z80-sdcc -mmcs51 ..." generates code for z80 and not for mcs51.

    I think it would be better if -m would have higher priority. This means just changing the sequence in function _findPort():
    - try to assign port by the name of the executable
    - try to assign port by command line option

    Borut

    Borut

     
  • Frieder Ferlemann

    Hi Borut,
    thanks for #5474!

    > ""z80-sdcc -mmcs51 ..." generates code for z80 and not for mcs51."

    No, it already is as you want it to be:)
    (The variable "found" is checked in the loop condition of the 2nd loop,
    so a previously (by -m option) assigned port is not overriden.)

    Greetings,
    Frieder

     
  • Borut Ražem

    Borut Ražem - 2009-07-18

    Frieder,

    you are right, I haven't noticed that the for loop is executed only if found is false.
    Thanks for clarification.

    Borut

     

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