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Symbolic Equation Manipulator

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Programming Languages: Java

License: Open Software License 3.0 (OSL3.0)

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browse code, statistics, last commit on 2003-05-14 cvs -d:pserver:anonymous@equation.cvs.sourceforge.net:/cvsroot/equation login

cvs -z3 -d:pserver:anonymous@equation.cvs.sourceforge.net:/cvsroot/equation co -P modulename

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  • Dragging exponents can cause them to disappear

    This program is great! Thanks to its creator(s). There is one oddity about the handling of exponents. If I enter this new equation: X^N = Y ... and then I drag the "N" to the right side of the equation, it simply disappears. I end up with just X = Y. It does appear to handle the dragging of the exponent if I use a number rather than a variable, for example...

    2008-09-09 19:22:53 UTC by nobody

  • Apology and Good News

    Hello everybody. This is jamesahart speaking. I have an apology to make: I'm sorry for not coming here and seeing your bugs. I'm sorry for not fixing these critical bugs much sooner. I'm sorry for ignoring this site for so long. There was almost no traffic on here for the first two years of development, and so the extremely important habits of checking for comments regularly never really...

    2006-12-03 02:04:18 UTC by jamesahart

  • Comment: Order of operations violation

    ar should be interpreted as single variable with the name "ar", just like the expression pi will represent the variable "pi" rather than p*i. To get multiplication, you have to use either a space between the variables or a '*'.

    2006-12-03 01:40:38 UTC by jamesahart

  • Other equations as identities

    It would be nice if other equations could be used as identities in simplifying or manipulating equations. This would, for instance, let me enter some identities of my own that are useful in a particular setting and use them as if they were real identities. This is particularly useful when trying to reduce an equation using approximations.

    2006-09-26 05:35:53 UTC by tedunning

  • Order of operations violation

    I believe the following expression: ar is interpreted as a * r. This is good. However, the following expression: ar^m is apparently interpreted as (a * r)^m rather than a * r^m. Given that exponents take precedence in order of operations, isn't the latter preferable? I was playing around with geometric series equation and having a lot of trouble until I figured out that...

    2006-08-03 17:01:20 UTC by nobody

  • New webpage

    I have created a new web-page and blog about MathDrag'n (my new project name) at http:\\mathdragn.squarespace.com. Check it out!

    2005-03-01 21:32:47 UTC by jamesahart

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