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From: Martin Reuter <mreuter@gm...>  20101222 23:58:56

Sorry to bother you guys again, but I found out that matlabs sqrtm is based on complex schur decomposition (taken from LAPACK routines). That is more general than the eigenvalue decomposition and can deal with defective cases. Is Schur implemented in vnl? Could not really find it, only as part of solving generalized eigensystems. Thanks, Martin On Wed, 20101222 at 17:33 0500, Martin Reuter wrote: > Yes, std::sqrt seems to work, only need one sqrt anyway. > > Now I just need a fast way of computing the inverse of a complex 4x4 > matrix. using vnl_inverse gives an error: > > In function ‘vnl_matrix_fixed<T, 4u, 4u> vnl_inverse(const > vnl_matrix_fixed<T, 4u, 4u>&) [with T = std::complex<double>]’: > > vnl_inverse.h:114: error: no match for ‘operator==’ in ‘det == 0’ > > looks like it cannot deal with complex fixed matrices? > > Martin > > On Wed, 20101222 at 20:50 +0000, Peter Vanroose wrote: > > > is this (cpoly_roots) computationally efficient, or a lot > > > of overhead (have to solve this very often). > > > > I guess it's indeed a lot of overhead, certainly for something as simple as square root. Didn't measure this, though. > > > > > > > Another idea I had is to convert to std::complex and use > > > the provided sqrt function? Does that make sense? > > > > Of course. That's probably a lot better. But I'm not familiar enough with std::sqrt(std::complex<T>) to be sure about this; e.g.: which of the two square roots is returned by this function? > > > > > > > This brings me to another question about vcl_complex. Is > > > that a wrapper around std::complex? > > > > Yes. Or better said: it is (in most cases) just a #define for std::complex. > > So the two are (or should be) identical. > > > > > > > The vnl:numerics documentation says this: > > > "Compliance with the ANSI standard C++ library > > > The current draft of the ANSI standard (as at May 1996) > > > includes classes for 1dimensional vectors (valarray<T>) > > > and complex numbers (complex<T>). > > > There is no standard for matrices. > > > The current vnl classes are not implemented in terms of > > > valarray, as there is a potential performance hit, > > > but in the future they might be." > > > > > > So what's with complex ?? > > > > There is no vnl_complex, just vcl_complex (which is std::complex). > > > > > >  Peter. > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >  > Learn how Oracle Real Application Clusters (RAC) One Node allows customers > to consolidate database storage, standardize their database environment, and, > should the need arise, upgrade to a full multinode Oracle RAC database > without downtime or disruption > http://p.sf.net/sfu/oraclesfdevnl > _______________________________________________ > Vxlusers mailing list > Vxlusers@... > https://lists.sourceforge.net/lists/listinfo/vxlusers 
From: Martin Reuter <mreuter@gm...>  20101222 22:33:55

Yes, std::sqrt seems to work, only need one sqrt anyway. Now I just need a fast way of computing the inverse of a complex 4x4 matrix. using vnl_inverse gives an error: In function ‘vnl_matrix_fixed<T, 4u, 4u> vnl_inverse(const vnl_matrix_fixed<T, 4u, 4u>&) [with T = std::complex<double>]’: vnl_inverse.h:114: error: no match for ‘operator==’ in ‘det == 0’ looks like it cannot deal with complex fixed matrices? Martin On Wed, 20101222 at 20:50 +0000, Peter Vanroose wrote: > > is this (cpoly_roots) computationally efficient, or a lot > > of overhead (have to solve this very often). > > I guess it's indeed a lot of overhead, certainly for something as simple as square root. Didn't measure this, though. > > > > Another idea I had is to convert to std::complex and use > > the provided sqrt function? Does that make sense? > > Of course. That's probably a lot better. But I'm not familiar enough with std::sqrt(std::complex<T>) to be sure about this; e.g.: which of the two square roots is returned by this function? > > > > This brings me to another question about vcl_complex. Is > > that a wrapper around std::complex? > > Yes. Or better said: it is (in most cases) just a #define for std::complex. > So the two are (or should be) identical. > > > > The vnl:numerics documentation says this: > > "Compliance with the ANSI standard C++ library > > The current draft of the ANSI standard (as at May 1996) > > includes classes for 1dimensional vectors (valarray<T>) > > and complex numbers (complex<T>). > > There is no standard for matrices. > > The current vnl classes are not implemented in terms of > > valarray, as there is a potential performance hit, > > but in the future they might be." > > > > So what's with complex ?? > > There is no vnl_complex, just vcl_complex (which is std::complex). > > >  Peter. > > > > > > > > > > > > > > > > > > 
From: Peter Vanroose <peter_vanroose@ya...>  20101222 20:50:54

> is this (cpoly_roots) computationally efficient, or a lot > of overhead (have to solve this very often). I guess it's indeed a lot of overhead, certainly for something as simple as square root. Didn't measure this, though. > Another idea I had is to convert to std::complex and use > the provided sqrt function? Does that make sense? Of course. That's probably a lot better. But I'm not familiar enough with std::sqrt(std::complex<T>) to be sure about this; e.g.: which of the two square roots is returned by this function? > This brings me to another question about vcl_complex. Is > that a wrapper around std::complex? Yes. Or better said: it is (in most cases) just a #define for std::complex. So the two are (or should be) identical. > The vnl:numerics documentation says this: > "Compliance with the ANSI standard C++ library > The current draft of the ANSI standard (as at May 1996) > includes classes for 1dimensional vectors (valarray<T>) > and complex numbers (complex<T>). > There is no standard for matrices. > The current vnl classes are not implemented in terms of > valarray, as there is a potential performance hit, > but in the future they might be." > > So what's with complex ?? There is no vnl_complex, just vcl_complex (which is std::complex).  Peter. 
From: Martin Reuter <mreuter@gm...>  20101222 18:47:59

Thanks, is this (cpoly_roots) computationally efficient, or a lot of overhead (have to solve this very often). Another idea I had is to convert to std::complex and use the provided sqrt function? Does that make sense? This brings me to another question about vcl_complex. Is that a wrapper around std::complex? The vnl:numerics documentation says this: "Compliance with the ANSI standard C++ library The current draft of the ANSI standard (as at May 1996) includes classes for 1dimensional vectors (valarray<T>) and complex numbers (complex<T>). There is no standard for matrices. The current vnl classes are not implemented in terms of valarray, as there is a potential perfomance hit, but in the future they might be." So what's with complex ?? (also performance is spelled with a 2nd 'r'). best, Martin On Wed, 20101222 at 17:22 +0000, Peter Vanroose wrote: > Sure: since the two square roots of a complex number c are the two solutions of the equation x^2  c = 0, you can use class vnl_cpoly_roots. > > Example: > To find the two complex square roots of 3+4i (which are 2+i and 2i), compile&run the following: > > #include <vnl/algo/vnl_cpoly_roots.h> > #include <vcl_iostream.h> > int main() > { > vcl_complex<double> c(3.0,4.0); > vnl_vector<vcl_complex<double> > equation(2); > // Note: the coefficient in x^2 of the equation must be 1 > // (not to be placed in the equation vector); > // equation[0] is the second highest coefficient, etc. > equation[0] = 0; equation[1] = c; > vnl_cpoly_roots r(equation); > vcl_cout << "First square root of 3+4i is " << r.solns[0] > << "\nSecond square root is " << r.solns[1] << vcl_endl; > return 0; > } > >  Peter. > > > > > > > > > > > > > > >  > > >  Den ons 20101222 skrev Martin Reuter <mreuter@...>: > > > Från: Martin Reuter <mreuter@...> > > Ämne: [Vxlusers] complex squareroot? > > Till: vxlusers@... > > Datum: onsdag 22 december 2010 01:40 > > Hi, > > > > is there a way to compute a squareroot of a complex number > > in vnl? > > > > Actually what I am trying to achieve is to use > > vnl_complex_eigensystem > > on a real matrix to compute eigenvectors and complex > > eigenvalues, then > > compute the squareroot of the eigenvalues and finally the > > squareroot of > > the original matrix. Of course it would be nice to have a > > sqrtm > > functions (see matlab) to do all this for me. > > > > > > Thanks for any hints, Martin > > > > > >  > > Forrester recently released a report on the Return on > > Investment (ROI) of > > Google Apps. They found a 300% ROI, 38%56% cost savings, > > and breakeven > > within 7 months. Over 3 million businesses have gone > > Google with Google Apps: > > an online email calendar, and document program that's > > accessible from your > > browser. Read the Forrester report: http://p.sf.net/sfu/googleappssfnew > > _______________________________________________ > > Vxlusers mailing list > > Vxlusers@... > > https://lists.sourceforge.net/lists/listinfo/vxlusers > > > > 
From: Peter Vanroose <peter_vanroose@ya...>  20101222 17:22:40

Sure: since the two square roots of a complex number c are the two solutions of the equation x^2  c = 0, you can use class vnl_cpoly_roots. Example: To find the two complex square roots of 3+4i (which are 2+i and 2i), compile&run the following: #include <vnl/algo/vnl_cpoly_roots.h> #include <vcl_iostream.h> int main() { vcl_complex<double> c(3.0,4.0); vnl_vector<vcl_complex<double> > equation(2); // Note: the coefficient in x^2 of the equation must be 1 // (not to be placed in the equation vector); // equation[0] is the second highest coefficient, etc. equation[0] = 0; equation[1] = c; vnl_cpoly_roots r(equation); vcl_cout << "First square root of 3+4i is " << r.solns[0] << "\nSecond square root is " << r.solns[1] << vcl_endl; return 0; }  Peter.   Den ons 20101222 skrev Martin Reuter <mreuter@...>: > Från: Martin Reuter <mreuter@...> > Ämne: [Vxlusers] complex squareroot? > Till: vxlusers@... > Datum: onsdag 22 december 2010 01:40 > Hi, > > is there a way to compute a squareroot of a complex number > in vnl? > > Actually what I am trying to achieve is to use > vnl_complex_eigensystem > on a real matrix to compute eigenvectors and complex > eigenvalues, then > compute the squareroot of the eigenvalues and finally the > squareroot of > the original matrix. Of course it would be nice to have a > sqrtm > functions (see matlab) to do all this for me. > > > Thanks for any hints, Martin > > >  > Forrester recently released a report on the Return on > Investment (ROI) of > Google Apps. They found a 300% ROI, 38%56% cost savings, > and breakeven > within 7 months. Over 3 million businesses have gone > Google with Google Apps: > an online email calendar, and document program that's > accessible from your > browser. Read the Forrester report: http://p.sf.net/sfu/googleappssfnew > _______________________________________________ > Vxlusers mailing list > Vxlusers@... > https://lists.sourceforge.net/lists/listinfo/vxlusers > 
From: Martin Reuter <mreuter@gm...>  20101222 00:40:34

Hi, is there a way to compute a squareroot of a complex number in vnl? Actually what I am trying to achieve is to use vnl_complex_eigensystem on a real matrix to compute eigenvectors and complex eigenvalues, then compute the squareroot of the eigenvalues and finally the squareroot of the original matrix. Of course it would be nice to have a sqrtm functions (see matlab) to do all this for me. Thanks for any hints, Martin 