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From: Peter Vanroose <Peter.V<anroose@es...>  20011029 20:48:16

> By definition of the cos_angle, it is already symmetric: > cos_angle(a,b) = cos_angle(b,a) = a.b/(ab). Sure; sorry about the misunderstanding. I meant "nonoriented" instead of "symmetric". 
From: Andrew Fitzgibbon <awf@ro...>  20011029 20:16:30

I hate to ask, but are any test cases run on vxl? 
From: Andrew Fitzgibbon <awf@ro...>  20011029 20:15:58

Amitha: > I think it should simply be > acos( a.b / ab ) > since that is what most people refer to as the angle between two > vectors. Agreed. 
From: Andrew Fitzgibbon <awf@ro...>  20011029 20:05:18

> Apparently In the sense of "obviously", or that you have other information? A. 
From: Amitha Perera <perera@cs...>  20011029 20:03:37

> Apparently this is meant to give "symmetric" output, i.e., > angle(a,b) == angle(b,a). By definition of the cos_angle, it is already symmetric: cos_angle(a,b) = cos_angle(b,a) = a.b/(ab). The current implementation gives ^ / / A / B </..... B as the "angle", which is the smallest angle provided the "vectors" are undirected. Is this what is intended? I think it should simply be acos( a.b / ab ) since that is what most people refer to as the angle between two vectors. Amitha. 
From: Peter Vanroose <Peter.V<anroose@es...>  20011029 19:54:08

> The current implementation of angle in vnl_vector.txx is > acos( abs( cos_angle(a,b) ) ) > > Why is the abs there? Apparently this is meant to give "symmetric" output, i.e., angle(a,b) == angle(b,a). Should probably be documented. Peter. 
From: Amitha Perera <perera@cs...>  20011029 19:10:16

Hi all The current implementation of angle in vnl_vector.txx is acos( abs( cos_angle(a,b) ) ) Why is the abs there? Thanks, Amitha. 