I have a dataset, which has backslash character in some of the Subject URIs. Whenever I try to use such URI in SPARQL Query, Virtuoso gives me this:
Virtuoso 37000 Error SP030: SPARQL compiler, line 0: Invalid character in SPARQL expression at '\'
Do I need to escape backslash somehow? I tried to replace it with "%5C" and "%5c" but that just gives me empty result set.
Example of URI: