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#3 Bugs in 0.1.5

closed-fixed
nobody
5
2005-03-01
2005-01-15
Anonymous
No

[andyrowe@mackintosh.co.uk] Andy Rowe.

I've downloaded, installed and managed to get your
software running. I know this is an early release and I
am by no way a programmer!

I've found a number of bugs that I hope you don't mind
me pointing out.

I've been looking for a EASY way for managers to submit
staff holidays in different locations, and allowing
reporting from that. Your software is a good start into
that, using mysql makes the reporting easier.

Unbooking - I noticed that this was fixed? Sorry, still a
problem. It no longer shows in the calendar, but does
show in the summary. Trying to unbook it again from
there fails. [Looks like a day -/+ 1 error?]

I will continue to test and report others I've found if
that's OK with you.

I also have some ideas on some other features tat
would be nice, and some concept ideas. As I said I'm no
programmer but would like to use your software if
possible.

Discussion

  • Logged In: YES
    user_id=860983

    This issue /will/ be sorted in the next release - I though I
    had got it already!

     
    • status: open --> closed-fixed
     
  • Logged In: YES
    user_id=860983

    Finally tracked it down!
    while ($data=mysql_fetch_array($mydb)) { // pull the data
    out of the database and stick it in arrays to build the
    table below
    $booked[$data["Day"]-$first]=$data["EmpID"];
    $booked_by[$data["Day"]-$first]=$data["Name"];
    }
    should be

    while ($data=mysql_fetch_array($mydb)) { // pull the data
    out of the database and stick it in arrays to build the
    table below
    $booked[$data["Day"]-$first+1]=$data["EmpID"];
    $booked_by[$data["Day"]-$first+1]=$data["Name"];
    }
    in calendar.php

     
  • Logged In: NO

    I have found, a error, while making public holys date

    when mak a public holy date, it wile then says will not make
    the corect day, but the day after.

    i fix myself by chaning

    $booked[$data["Day"]-$first]=$data["EmpID"];
    $booked_by[$data["Day"]-$first]=$data["Name"];
    }

    to

    while ($data=mysql_fetch_array($mydb)) { // pull the data
    out of the database and stick it in arrays to build the
    table below
    $booked[$data["Day"]-$first+1]=$data["EmpID"];
    $booked_by[$data["Day"]-($first-1)]=$data["Name"];
    }
    in calendar.php

    ----------------------------------------

    I write the message, althroug you have fix the error,

    because of the () it s be the same