I have the following code in my XSLT to get an expected result of "<a href="./Media/Helipad2.avi">Video on Deck, VD1.1</a>".
 
<a>
      <xsl:attribute name="href">
               .<xsl:value-of select="RRLInfo/IMIInfo/IMISource"/>
      </xsl:attribute>
      <xsl:value-of select="$MaterialText"/>
</a>
 
However, I get the result of:
 
"<a href="%0A%09%09%09%09%09%09%09%09%09%09%09./Media/Helipad2.avi">
                            (View Video on Deck )
                           </a>"
 
Obviously, the resulting HTML file cannot resolve this reference.
 
If I change my code to the following, then I get the expected result.
 
<a>
      <xsl:attribute name="href"> .<xsl:value-of select="RRLInfo/IMIInfo/IMISource"/>
      </xsl:attribute>
      <xsl:value-of select="$MaterialText"/>
</a>

I am trying to make my XSL file very readable. Is there anything to do other than just bite the bullet and format the XSL file as in the second coding?
 
(BTW, the first coding works fine using MSXML.)
 
Thanks very much!
 
Teresa
 
 
Teresa Rippeon
ManTech
9189 Red Branch Rd.
Columbia, MD 21045
410-772-3452
teresa.rippeon@mantech-stc.com