Re: [Oorexx-users] .Package~new question

[Rick M. <obj...@gm...>]

On Tue, Feb 12, 2013 at 6:06 PM, Mark Miesfeld <mie...@gm...> wrote:

> On Tue, Feb 12, 2013 at 2:51 PM, Staffan Tylen <sta...@gm...>wrote:
>
>> I'm fiddling with the .Package class and have found that if I create a
>> new package from an array of rexx code, the new package is immediately
>> executed by the init method. Is this the way it is supposed to work?
>> Example:
>>
>> a=.array~new
>> a~append("say 'hi this is me'")
>> a~append("say 'bye'")
>> p=.package~new("package1",a)
>>
>>
> I haven't played with the .Package class much, but it says this in the doc:
>
> The files loaded by ::REQUIRES are also contained in Package class
> instances.
>
> So, I think that p = .Package~new()
>
> is going to behave like:
>
> ::requires 'p.txt'
>
> and if p.txt is
>
> say 'hi this is me'
> say 'bye'
>
> Then when you require p.txt those 2 lines of code are going to run.  Which
> is what happens in your test.  Change your test to this
>
> a=.array~new
> a~append("::routine speak public")
> a~append("say 'hi this is me'")
> a~append("say 'bye'")
> a~append("return 0")
> p=.package~new("package1",a)
> r = speak()
>
> and try it.
>
> Although I just did and it didn't work as I expected.  But, it is more
> like what I think should work.
>


Mark, speak() did not work because creating the package does not
automatically add the package to the current context.  You'd need to add

  .context~package~addPackage(p)

to add it to the namespace.

or you can pull the speak routine object from the package and call it.

Rick

>
> --
> Mark Miesfeld
>
>
>
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