[ omegat-Bugs-1680081 ] Search: simple wilcards do not work

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Bugs item #1680081, was opened at 2007-03-13 19:31
Message generated for change (Settings changed) made by didierbr
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https://sourceforge.net/tracker/?func=detail&atid=520347&aid=1680081&group_id=68187

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Category: Application
Group: 1.6
Status: Open
Resolution: Fixed
Priority: 5
Private: No
Submitted By: Didier Briel (didierbr)
>Assigned to: tiago (klain)
Summary: Search: simple wilcards do not work

Initial Comment:
In Search, it was possible to use simple wildcards (* and ?).

Since (I believe) the possibility to use regexps was introduced, it seems the simple wildcards (when not in regexp mode) do not work anymore.

Didier


----------------------------------------------------------------------

Comment By: Didier Briel (didierbr)
Date: 2007-06-04 14:00

Message:
Logged In: YES 
user_id=1343245
Originator: YES

Fixed in CVS.
The correction was contributed by Tiago Saboga.
Copy of the message in OmTdev:
Here is the patch:


# This patch file was generated by NetBeans IDE
# Following Index: paths are relative to:
/home/tiago/src/omegat-cvs/omegat/src/org/omegat/util
# This patch can be applied using context Tools: Patch action on
respective folder.
# It uses platform neutral UTF-8 encoding and \n newlines.
# Above lines and this line are ignored by the patching process.
Index: StaticUtils.java
*** /home/tiago/src/omegat-cvs/omegat/src/org/omegat/util/StaticUtils.java
Base (1.56)
--- /home/tiago/src/omegat-cvs/omegat/src/org/omegat/util/StaticUtils.java
Locally Modified (Based On 1.56)
***************
*** 759,766 ****
          else {
              // convert * (0 or more characters) and ? (0 or 1
character)
              // to their regex equivalents (\S* and \S? respectively)
!             text = text.replaceAll("\\?", "\\S?"); // do ? first, or *
will be converted twice
!             text = text.replaceAll("\\*", "\\S*");
          }
  
          return text;
--- 759,766 ----
          else {
              // convert * (0 or more characters) and ? (0 or 1
character)
              // to their regex equivalents (\S* and \S? respectively)
!             text = text.replaceAll("\\?", "\\\\S?"); // do ? first, or *
will be converted twice
!             text = text.replaceAll("\\*", "\\\\S*");
          }
  
          return text;




----------------------------------------------------------------------

You can respond by visiting: 
https://sourceforge.net/tracker/?func=detail&atid=520347&aid=1680081&group_id=68187