From: SourceForge.net <no...@so...> - 2008-05-28 21:37:31
|
Bugs item #1977146, was opened at 2008-05-28 23:37 Message generated for change (Tracker Item Submitted) made by Item Submitter You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1977146&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core - Simplification Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Robert Marik (robertmarik) Assigned to: Nobody/Anonymous (nobody) Summary: radexpand does not work as explained in documentation Initial Comment: >From maxima discussion list: Maxima manual states the following --------------------- When radexpand is false, certain transformations are inhibited. radcan (sqrt (1-x)) remains sqrt (1-x) and is not simplified to %i sqrt (x-1). radcan (sqrt (x^2 - 2*x + 11)) remains sqrt (x^2 - 2*x + 1) and is not simplified to x - 1. --------------------- Neglecting the typo in radcan (sqrt (x^2 - 2*x + 11)) which should be probably radcan (sqrt (x^2 - 2*x + 1)), I get the answer x-1 also with radexpand:false. Moreover, sqrt(1-x) remains sqrt(1-x) even with radexpand:true. Is the documentation of radcan obsolete? Robert Marik reponse of Richard Fateman radexpand was inserted by someone else, after the code was written in 1970. I do not know if the documentation or the program is buggy, since I'm not sure what was intended. RJF ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1977146&group_id=4933 |