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From: SourceForge.net <noreply@so...>  20090907 21:12:54

Bugs item #1713067, was opened at 20070504 15:36 Message generated for change (Comment added) made by dgildea You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1713067&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Limit Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Stavros Macrakis (macrakis) Assigned to: Nobody/Anonymous (nobody) Summary: limit/integrate wrong Initial Comment: limit('integrate(t,t,0,x)/x,x,inf); Is 'limit('integrate(t,t,0,x),x,inf) positive, negative, or zero? pos; => 0 Of course the correct answer is INF, since integrate(t,t,0,x)/x == x/2 More complicated examples (correct answer is INF) limit(integrate(t/log(t),t,2,a)/a,a,inf) => 0 limit(integrate(t/log(t),t,x,2*x)/x,x,inf) => 0  >Comment By: Dan Gildea (dgildea) Date: 20090907 17:12 Message: Fixed in limit.lisp rev 1.80. (%i2) limit('integrate(t,t,0,x)/x,x,inf); (%o2) 'limit(('integrate(t,t,0,x))/x,x,inf) (%i3) limit(integrate(t/log(t),t,2,a)/a,a,inf); Is a2 positive, negative, or zero? p; (%o3) inf (%i4) limit(integrate(t/log(t),t,x,2*x)/x,x,inf); Is x positive, negative, or zero? p; Is 2*x1 positive, negative, or zero? p; Is x1 positive, negative, or zero? p; (%o4) 'limit(gamma_incomplete(0,2*log(x))/x gamma_incomplete(0,2*log(2*x))/x,x,inf) Indefinite integral are still buggy: (%i5) limit('integrate(x,x)/x,x,inf); (%o5) 0  Comment By: Stavros Macrakis (macrakis) Date: 20070504 17:58 Message: Logged In: YES user_id=588346 Originator: YES Re the anonymous comments: > Maybe you should try your 1st example without "'" before "integrate": > limit(integrate(t,t,0,x)/x,x,inf); gives the correct answer! Well, of course it does; Maxima can calculate a closed form for that integral. I was using that as a *simple* example of a nounform integral where limit gives the wrong answer. > And for your ´more complicated´ examples: > What other answers do you expect, when Maxima isn´t able to solve the > definite integrals??? First of all, I expect not to get an *incorrect* answer, 0. If Maxima can't calculate the correct answer, it should return a noun form. Secondly, in many cases it is possible to calculate the limit without being able to calculate a closedform integral. For example, limit( integrate( exp(t)/t, t, 1, x) , x, inf) = inf (I'm surprised that integrate(exp(t)/t,t,1,inf) doesn't report it's divergent, but it doesn't...) limit( integrate( t^5/(t^7+log(t)), x, x+1), x, inf) = 0 etc. It turns out that limit doesn't have any special code for integrals like this, but it certainly *could*.  Comment By: Nobody/Anonymous (nobody) Date: 20070504 16:34 Message: Logged In: NO Maybe you should try your 1st example without "'" before "integrate": limit(integrate(t,t,0,x)/x,x,inf); gives the correct answer! And for your ´more complicated´ examples: What other answers do you expect, when Maxima isn´t able to solve the definite integrals???  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1713067&group_id=4933 
From: SourceForge.net <noreply@so...>  20090907 11:43:41

Bugs item #2853506, was opened at 20090907 11:43 Message generated for change (Tracker Item Submitted) made by nobody You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2853506&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Limit Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: limit(1  (1/2)^inf) > inf Initial Comment: OK, but could be 0: (%i2) limit((1/2)^inf); (%o2) (1)^inf/2^inf Not OK: (%i3) limit(1  (1/2)^inf); (%o3) inf  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2853506&group_id=4933 