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From: SourceForge.net <noreply@so...>  20080713 19:45:08

Bugs item #1847543, was opened at 20071209 17:57 Message generated for change (Comment added) made by dgildea You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1847543&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None >Status: Closed >Resolution: Fixed Priority: 7 Private: No Submitted By: Henrik Holst (hholst) >Assigned to: Dan Gildea (dgildea) Summary: Integration problem of a special periodic function Initial Comment: Hello Maxima developers, I am trying to integrate f(x) := 1/(11/10+sin(2*%pi*x)); from x=0 to x=1. It works in Mathematica 5, and gives the correct answer: 10/Sqrt(21) Maxima gives no answer however it gives an answer if I input g(x) := 1/(11/10+sin(x)); and integrate from x=0 to x=2*%pi. Also (maybe related), if you try to integrate with a constant "a" times x instead of 2*%pi*x, maxima asks for the sign of a. If the reply is "positive" it just comsumes 100% CPU. [1] [1] Investigation by lindi @ freenode irc Maxima version: 5.12.0 Maxima build date: 21:41 7/20/2007 host type: x86_64unknownlinuxgnu lispimplementationtype: GNU Common Lisp (GCL) lispimplementationversion: GCL 2.6.7  >Comment By: Dan Gildea (dgildea) Date: 20080713 15:45 Message: Logged In: YES user_id=1797506 Originator: NO Fixed in sin.lisp by generalizing simpletrigarg to handle nonnumber coefficients. (%i20) integrate(1/(11/10+sin(2*%pi*x)), x); (%o20) 10*atan((22*sin(2*%pi*x)/(cos(2*%pi*x)+1)+20)/(2*sqrt(21))) /(sqrt(21)*%pi) (%i21) integrate(1/(11/10+sin(a*x)), x); (%o21) 20*atan((22*sin(a*x)/(cos(a*x)+1)+20)/(2*sqrt(21)))/(sqrt(21)*a) Not sure why rischint can't handle this expression. (%i23) risch(1/(11/10+sin(2*%pi*x)), x); (%o23) 10*'integrate((5*cos(2*%pi*x)*sin(4*%pi*x)5*sin(2*%pi*x)*cos(4*%pi*x) +11*sin(2*%pi*x)^2 +5*sin(2*%pi*x) +11*cos(2*%pi*x)^2) /(25*sin(4*%pi*x)^2+110*cos(2*%pi*x)*sin(4*%pi*x) +25*cos(4*%pi*x)^2 +(110*sin(2*%pi*x)50)*cos(4*%pi*x) +121*sin(2*%pi*x)^2+110*sin(2*%pi*x) +121*cos(2*%pi*x)^2+25),x)  Comment By: Robert Dodier (robert_dodier) Date: 20080614 21:14 Message: Logged In: YES user_id=501686 Originator: NO same behavior observed in 5.14.99rc1.  Comment By: Raymond Toy (rtoy) Date: 20071211 12:40 Message: Logged In: YES user_id=28849 Originator: NO It's a bug that maxima can't compute the first integral. For the last case, maxima has correctly determined the antiderivative. It is now trying to substitute the limits carefully because the antiderivative contains inverse trig functions. I think it's getting stuck there.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1847543&group_id=4933 
From: SourceForge.net <noreply@so...>  20080713 02:57:24

Bugs item #2016518, was opened at 20080712 01:28 Message generated for change (Comment added) made by robert_dodier You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2016518&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: None Group: None Status: Open >Resolution: Rejected Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: definition of functions Initial Comment: When defining a function using some previous result no error message is issued. If then a function value is called one obtains a wrong answer. The attached file illustrates that  >Comment By: Robert Dodier (robert_dodier) Date: 20080712 20:57 Message: Logged In: YES user_id=501686 Originator: NO For the record here is the content of the bug.wxm file: bug_report(); x; f(x):=%o2; f(3); I don't see any problem here  probably there is just a misunderstanding about how Maxima works. To the original poster: you might consider asking for help on the Maxima mailing list. See: http://maxima.sourceforge.net/maximalist.html I guess we can leave this report open for a while and then close it as a nonbug.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2016518&group_id=4933 
From: SourceForge.net <noreply@so...>  20080713 02:53:03

Bugs item #1811968, was opened at 20071011 20:27 Message generated for change (Settings changed) made by robert_dodier You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1811968&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core Group: None Status: Closed >Resolution: Fixed Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: echelon error Initial Comment: The "echelon()" function calculates a matrix which cannot be arrived at by elementary row operations. Look, the rank even changes! PK  Comment By: Andrej Vodopivec (andrejv) Date: 20080615 14:34 Message: Logged In: YES user_id=1179910 Originator: NO Then rank function already sets algebraic to true in case there are algebraic numbers in the matrix. Attached a patch which does the same for the echelon function. File Added: matrix.lisp.patch  Comment By: Robert Dodier (robert_dodier) Date: 20080614 19:05 Message: Logged In: YES user_id=501686 Originator: NO Here's the content of the jpeg. b:matrix([1/2, sqrt(3)/2, 1, 0], [sqrt(3)/2, 1/2, 0, 1], [1, 0, 1, sqrt(3)/2], [0, 1, sqrt(3)/2, 1/2]); rank(b); => 3 echelon(b); => matrix([1,sqrt(3),2,0],[0,1,sqrt(3)/2,1/2],[0,0,1,0],[0,0,0,1]) rank(echelon(b)); => 4 triangularize(b); => matrix([1,sqrt(3),2,0],[0,2,sqrt(3),1],[0,0,6,0],[0,0,0,0])  Comment By: Barton Willis (willisbl) Date: 20071012 19:26 Message: Logged In: YES user_id=895922 Originator: NO A workaround is to set algebraic to true. Maybe echelon (and rank) should set algebraic to true. PS Instead of a jpg file, next time send a text only bug report: (1) it's easy to do (2) it doesn't require that the reader do any retyping (3) it has no security risks for the reader (4) it's much more likely that somebody will read your report.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1811968&group_id=4933 